molarity = moles / V in L
Molarity = 6.10 M
moles = 0.355
V = ?
V = moles / molarity = 0.355 / 6.10
V = 0.058 L
V = 58.0 mL
volume of NaOH needed to prepare 0.355 mol of NaOH = 58.0 mL
answer = 58.0 mL
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