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2) Suppose we want to estimate the mean mortage layment for homes in Denver. Suppose that...

2) Suppose we want to estimate the mean mortage layment for homes in Denver. Suppose that it is known from past data thag the mean monthly mortage payment is $2500 with a standard deviation of $1000. If we want to be 92% confident that lur sample mean is within $300 of the population mean, what is the recommended sample size?

3) Suppose we want to estimate the proportion of homes in Denver that are valued at over $1,000,000. Suppose that it is known from past data that the proprotion of such homes in Denver is 15%. If we want to be 82% confident that our sample proportion is within 4% of the population proportion, what is the recommended sample size?

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Answer #1

2)

Given that,

Population standard deviation = = 1000

Margin of error = E = 300

Z/2 = 1.75

sample size = n = [Z/2* / E] 2

n = [1.75 * 1000 / 300]2

n = 34.02

Sample size = n = 35

3)

Given that,

= 0.15

1 - = 0.85

margin of error = E = 0.04

Z/2 = 1.34

sample size = n = (Z / 2 / E)2 * * (1 - )

= (1.34 / 0.04)2 * 0.15 * 0.85

= 143.08

sample size = n = 144

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