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Calculate Δ?, Δ?, Δ????, ??? Δ????? when 4.31 moles of H2O(g) condenses at 58 oC at...

Calculate Δ?, Δ?, Δ????, ??? Δ????? when 4.31 moles of H2O(g) condenses at 58 oC at 1.0 atm until it is a liquid. Assume that all heat capacities and enthalpy changes are constant with values of: ??,? = 75.3 ? ? ??? , ??,? = 35.9 ? ? ??? , ???? = 100 ?, Δ???? 40.7 ?? ??�

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Answer #1

Reaction for the condensation: H2O(g) <----> H2O(l)

ΔCp = (Cp)H2O(l) - (Cp)H2O(g) = 75.3 - 35.9 = 39.4 J/K.mol

The change in temperature (ΔT) = 100 - 58 = 42 oC or 42 K

The no. of moles of H2O (n) = 4.31 mol

Now, ΔH = n*ΔCp*ΔT = 4.31 mol * 39.4 J/K.mol * 42 K = 7132.188 J or 7.132 kJ

Now, ΔS = ΔH/T = 7132.188 J/(58+273) K = 21.547 J/K

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