Question

Concepts: Pointers and pointer arrays

Write a program to read in a phrase from the keyboard, re-display the text, and display a message on the following line giving the text's status as a palindrome. Do not use any arrays or subscripting in this program, except for arrays of pointers.

A palindrome is a word or phrase which is the same backwards as forwards; for example "civic", "toot", and "radar" are palindrome words; each word is spelled the same left to right, as right to left.
"A man, a plan, a canal - Panama!" is a palindrome phrase; ignoring case, spaces and punctuation,
the phrase is spelled the same left to right, as right to left.

Determine if the phrase entered by the user is a palidrome. Setting a pointer to the first character in the entered text, and another pointer to the last character, move the pointers toward the center comparing the characters. Skip over anything that isn't a letter. If the pointers meet before finding any differences, you have a palindrome. Display a message to that effect on the next console line.

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Answer 1

if you have any doubts, please give me comment...

#include<iostream>

#include<cctype>

#include<cstring>

using namespace std;

#define MAX_SIZE 100

int main(){

char *phrase = new char[MAX_SIZE];

cout<<"Enter phrase: ";

cin.getline(phrase, MAX_SIZE);

char *startPtr = phrase;

char *endPtr = phrase+strlen(phrase)-1;

bool isPalindrome = true;

while(startPtr<endPtr){

// cout<<*startPtr<<" "<<*endPtr<<endl;

if(ispunct(*startPtr) || isspace(*startPtr))

startPtr++;

else if(ispunct(*endPtr) || isspace(*endPtr))

endPtr--;

else if(toupper(*startPtr) != toupper(*endPtr)){

isPalindrome = false;

break;

}

else{

startPtr++;

endPtr--;

}

}

if(isPalindrome)

cout<<"Entered phrase "<<phrase<<" is a palindrome"<<endl;

else

cout<<"Entered phrase "<<phrase<<" is NOT a palindrome"<<endl;

return 0;

}