.To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is...
.To determine the concentration of ethanol in cognac a 5.00 mL sample of the cognac is diluted to 0.500 L. Analysis of the diluted cognac gives an ethanol concentration of 0.0844 M. What is the molar concentra - tion of ethanol in the undiluted cognac?
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.To determine the concentration of ethanol in cognac a 5.00 mL
sample of the cognac is...
1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of...
1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into a 500-mL volumetric flask and diluting to volume....
A 13.0 mL aliquot of a flouride sample solution was diluted to 250 mL in a...
A 13.0 mL aliquot of a flouride sample solution was diluted to 250 mL in a volumetric flask. The F- concentration of this DILUTED sample was determined with a F- ion selective electrode and found to be 3.1 mg/L. What is the concentration of F- in the original, undiluted sample?
Add 1.5 mL of the 1.0%(v/v) ethanol (mL) to 8.5 mL of deionized water. The ethanol...
Add 1.5 mL of the 1.0%(v/v) ethanol (mL) to 8.5 mL of deionized water. The ethanol standard in the test tube will have a final concentration of ____ %(v/v) ethanol? Add 1.0 mL of wine that has been diluted by a factor of 100, to a test tube and add 20 drops of sulfuric acid to it. The concentration of the diluted wine sample was found to be 0.23%(v/v) ethanol. Using the procedure stated, what was the original concentration of...
A 6.04 g sample of a solid containing Ni is dissolved in 20.0 mL water. A...
A 6.04 g sample of a solid containing Ni is dissolved in 20.0 mL water. A 5.00 mL aliquot of this solution is diluted to 100.0 mL and analyzed in the lab. The analyzed solution was determined to contain 6.88 ppm Ni . Determine the molar concentration of Ni in the 20.0 mL solution. *concentration= ? M Determine the mass, in grams, of Ni in the original sample. *mass= ? g Determine the weight percent of Ni in the sample....
Suppose 5.00 mL of a 1.00 M stock solution is diluted to 25.00 mL. Afterwards, 5.00...
Suppose 5.00 mL of a 1.00 M stock solution is diluted to 25.00 mL. Afterwards, 5.00 mL of this solution is diluted to 25.00 mL. What is the concentration of the final solution?
20.00 mL unknown sample is diluted to 250.0 mL. Absorbance is 0.2430 Absorbance for 70.00 ppm...
20.00 mL unknown sample is diluted to 250.0 mL. Absorbance is 0.2430 Absorbance for 70.00 ppm std is .950 What is ppm concentration in the original undiluted sample?
a) Calculate the final concentration when 25.0 mL of an 18.0 M HCl solution is diluted...
a) Calculate the final concentration when 25.0 mL of an 18.0 M HCl solution is diluted to 0.500 L. b) Calculate the volume required when an 8.50 M KOH solution is diluted to form 95.0 mL of a 0.500 M KOH solution
An aqueous ethanol solution (400 mL) was diluted to 4.00 L, giving a concentration of 0.0400...
An aqueous ethanol solution (400 mL) was diluted to 4.00 L, giving a concentration of 0.0400 M. The concentration of the original solution was _ M OA) 1.60 OB) 0.200 OC) 0.400 OD) 4.00 OE) 2.00 Gaseous mixtures A) are all homogeneous OB) can only contain molecules C) can only contain isolated atoms O D ) are all heterogeneous O E) must contain both isolated atoms and molecules
The method of standard additions was used to determine nitrite in a soil sample. A 1.00-ml...
The method of standard additions was used to determine nitrite in a soil sample. A 1.00-ml portion of the sample was mixed with 22.00 mL of a colorimetric reagent, and the nitrite was converted to a colored product that produced a blank-corrected absorbance of 0.300. To 51.00 mL of the original sample, 1.00 mL of a standard solution of 1.00×10 M nitrite was added. The same color-forming procedure was followed, and the new absorbance was 0.480. What was the concentration...
The method of standard additions was used to determine nitrite in a soil sample. A 1.00-ml portion of the sample was mi...
The method of standard additions was used to determine nitrite in a soil sample. A 1.00-ml portion of the sample was mixed with 22.00 mL of a colorimetric reagent, and the nitrite was converted to a colored product that produced a blank-corrected absorbance of 0.300. To 51.00 mL of the original sample, 1.00 mL of a standard solution of 1.00×10 M nitrite was added. The same color-forming procedure was followed, and the new absorbance was 0.480. What was the concentration...
20.00 mL unknown sample is diluted to 250.0 mL. Absorbance is 0.2430 Absorbance for 70.00 ppm std is .950 What is ppm concentration in the original undiluted sample?
An aqueous ethanol solution (400 mL) was diluted to 4.00 L, giving a concentration of 0.0400 M. The concentration of the original solution was _ M OA) 1.60 OB) 0.200 OC) 0.400 OD) 4.00 OE) 2.00 Gaseous mixtures A) are all homogeneous OB) can only contain molecules C) can only contain isolated atoms O D ) are all heterogeneous O E) must contain both isolated atoms and molecules
The method of standard additions was used to determine nitrite in a soil sample. A 1.00-ml portion of the sample was mixed with 22.00 mL of a colorimetric reagent, and the nitrite was converted to a colored product that produced a blank-corrected absorbance of 0.300. To 51.00 mL of the original sample, 1.00 mL of a standard solution of 1.00×10 M nitrite was added. The same color-forming procedure was followed, and the new absorbance was 0.480. What was the concentration...
The method of standard additions was used to determine nitrite in a soil sample. A 1.00-ml portion of the sample was mixed with 22.00 mL of a colorimetric reagent, and the nitrite was converted to a colored product that produced a blank-corrected absorbance of 0.300. To 51.00 mL of the original sample, 1.00 mL of a standard solution of 1.00×10 M nitrite was added. The same color-forming procedure was followed, and the new absorbance was 0.480. What was the concentration...
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