The coefficent of static friction between the floor of a truck
and a box resting on it is 0.35. The truck is traveling at 81.3
km/hr. What is the least distance in which the truck can stop and
ensure that the box does not slide?
acceleration till which the box friction can withstand
a = ug = 0.35* 9.8 = 3.43 m/s^2
now, using 3rd equation of motion
d = v^2/ (2 a)
d = (81.3* 5 / 18)^2 / ( 2* 3.43)
d = 74.345 m
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