Question

The floor of a truck is loaded with crates. The coefficient of static friction between the crates and the floor is 0.25. If the truck is initially moving at a speed of 48.5 km/hr, in how short a distance can the truck be stopped without causing the crates to slide? Give the value of the distance in meters. Distance - Do not include units in the box below -- the units are already included in the statement above. ONLY WRITE the NUMERICAL VALUE. Include a negative sign if needed. Express your answer to three significant figures.

Answer 1

eve so when truck stops at constant acceleration from estial speed 48. Skooth, due to mestia of the crates, there is a horizontal force acting on the crate in direction of motion of truck. & storisontal (f) = manaxt force mal accelevation of truck mass of crates The slide, only if following condition is crates donot satisfied- & fa teman had e Here tere for is maxionon static frictisnal force maxon acceleration of truck is given by T & mamax = -fsmax - 4 FN = mz opamad -- ll off & anax - - Lord = -0.25x9, 8 (anay -2.45 m2 so, the shortest distance trareved by truck- & V² = V.² + 2ax (Ar sport), v=ons 12.000 dos alarVol 2X2,45) Se short 2 max. & Vi= 13.47 m/s Bota 37.0357 ma