The tires of a car make 94 revolutions as the car reduces its speed uniformly from 86.0 km/hkm/h to 63.0 km/hkm/h. The tires have a diameter of 0.90 mm.
A; What was the angular acceleration of the tires?
b: What was the angular acceleration of the tires?
c: If the car continues to decelerate at this rate, how far does it go? Find the total distance.
The tires of a car make 94 revolutions as the car reduces its speed uniformly from...
The tires of a car make 94 revolutions as the car reduces its speed uniformly from 90.0 km/h to 63.0 km/h. The tires have a diameter of 0.88 m. Part A. What was the angular acceleration of the tires? Part B. If the car continues to decelerate at this rate, how much more time is required for it to stop? Part C. If the car continues to decelerate at this rate, how far does it go? Find the total distance.
The tires of a car make 62 revolutions as the car reduces its speed uniformly from 92.0 km/h to 63.0 km/h. The tires have a diameter of 0.82 m. part a What was the angular acceleration of the tires? part b If the car continues to decelerate at this rate, how much more time is required for it to stop? part c If the car continues to decelerate at this rate, how far does it go? Find the total distance.
The tires of a car make 93 revolutions as the car reduces its speed uniformly from 92.0 km/h to 60.0 km/h. The tires have a diameter of 0.86 m. A)What was the angular acceleration of the tires? B)If the car continues to decelerate at this rate, how much more time is required for it to stop? C)If the car continues to decelerate at this rate, how far does it go? Find the total distance.
The tires of a car make 83 revolutions as the car reduces its speed uniformly from 95.0 km/h k m / h to 59.0 km/h k m / h. The tires have a diameter of 0.82 m m.What was the angular acceleration of the tires?If the car continues to decelerate at this rate, how much more time is required for it to stop?If the car continues to decelerate at this rate, how far does it go? Find the total distance?
The tires of a car make 88 revolutions as the car reduces its speed uniformly from 90.0 km/h to 64.0 km/h. The tires have a diameter of 0.82 m. Part A What was the angular acceleration of the tires? Part B If the car continues to decelerate at this rate, how much more time is required for it to stop? Express your answer to two significant figures and include the appropriate units. Part C If the car continues to decelerate...
The tires of a car make 83 revolutions as the car reduces its speed uniformly from 90.0 km/h to 63.0 km/h. The tires have a diameter of 0.82 m. Part A What was the angular acceleration of the tires? Express your answer using two significant figures. α = rad/s2 Part B If the car continues to decelerate at this rate, how much more time is required for it to stop? Express your answer to two significant figures and include the...
The tires of a car make 95 revolutions as the car reduces its speed uniformly from 95.0 km/hkm/h to 55.0 km/hkm/h. The tires have a diameter of 0.88 m Angular acceleration of the tires: -2 rad/s2 A. If the car continues to decelerate at this rate, how much more time is required for it to stop? Express your answer to two significant figures and include the appropriate units. B. If the car continues to decelerate at this rate, how far...
The tires of a car make 56 revolutions as the car reduces its speed uniformly from 93 km/h to 50 km/h . The tires have a diameter of 0.76 m . A)What was the angular acceleration of the tires? B)If the car continues to decelerate at this rate, how much more time is required for it to stop?
Const Part A The tires of a car make 78 revolutions as the car reduces its speed uniformly from 90.0 km/h to 60.0 km/h. The tires have a diameter of 0.88 m. What was the angular acceleration of the tires? Express your answer using two significant figures. a = -1.8 rad/s? Subm Previous Answers Correct Part B If the car continues to decelerate at this rate, how much more time is required for it to stop? Express your answer to...
ASearch PHYS 110 Course Home Problem 8.22 6of15 (?) PartA Constants The tires of a car make 94 revolutions as the car reduces its speed uniformly from 94.0 km/h to 65.0 km/h. The tires have a diamoter of 0.86 m. What was the angular aoceleration of the tires? Express your answer using two significant figures. Correct Part B ifthe car continues to decelerate at this rato, how much more time is required fr it to stop? Express your answer to...