The activation energy for the gas phase decomposition of difluoroperoxide is 72.4 kJ. F2O2F2 + O2...

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The activation energy for the gas phase decomposition of difluoroperoxide is 72.4 kJ. F2O2F2 + O2...

The activation energy for the gas phase decomposition of difluoroperoxide is 72.4 kJ. F2O2F2 + O2 The rate constant at 238 K is 7.77×10-4 /s. The rate constant will be ___ /s at 279 K.

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Answer 1

Answer #1

Solution:

The integrated Arhenious equation is written as:

ln (k₂/k₁) = Ea/R [T₂-T₁/T₁T₂]

Given that,

k1 = 7.77×10^-4 sec-1 , T₁ = 238 K , T2 = 279 K and Ea = 72.4 KJ = 72400 J, K₂ =?

On putting the above values in equation, we get,

ln (k₂/k₁) = Ea/R [T₂-T₁/T₁T₂]

ln (k₂/7.77×10^-4 sec-1) =(72400 J /8.314 J K^-1 mol^-1) x [279 -238 /279 x 238]

ln (k₂/7.77×10^-4 sec-1) = 5.377

log (k₂/7.77×10^-4 sec-1) = 5.377/2.303 [ ln =2.303 log]

log (k₂/7.77×10^-4 sec-1) = 2.335

k2/7.77×10^-4 sec-1 = antilog 2.335 = 216.27

k2 = 7.77×10^-4 sec-1 x 216.27 = 1.68 x 10^-1 = 0.168 sec-1

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Answer 2

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The activation energy for the gas phase decomposition of difluoroperoxide is 72.4 kJ. F2O2F2 + O2...

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