Question

In this assignment, you will write one (1) medium size C program. The program needs to be structured using multiple functions, i.e., you are required to organize your code into distinct logical units. The following set of instructions provide the specific requirements for the program. Make sure to test thoroughly before submitting.

Write   a   program,   named   program1.c,   that   reads   and   processes   employee   records   (data   about   an   employee).   Each   employee   record   must   be   stored   using   a   struct   that   contains   the   following   fields:
• Name       o All   alphabetic.   o Max   of   60   characters   long.   o Includes   first,   middle,   and   last   name,   separated   by   spaces.   It   is   not   necessary   to   split   the   name   into   separate   fields.
-   Mailing   Address       o This   field   is   a   struct   embedded   within   the   employee   struct,   containing   the   following   fields:  
- Street   address   (max   49   chars).   § City   name   (max   29   chars).  
-  Two-character   state   abbreviation.   No   spaces.  
- Zip   code   (5-digit   number).   No   spaces.   Process   as   character   data.
-   Annual   salary   (a   float).   No   punctuation   or   dollar   sign.  
  
The   database   consists   of   a   collection   of   employee   records.   You   may   assume   that   this   program   is   for   a   small   business,   so   no   more   than   50   employee   records   need   to   be   stored.   However,   the   exact   number   is   not   known   beforehand.  
  
Users   will   enter   all   of   the   data   for   each   employee   in   a   single   line   of   text:   • Records   may   be   typed   at   the   console   or   stored   in   a   file.   Hence,   it   is   important   to   test   using   both   interactive   user   input   and   input   redirection.   o Make   sure   to   test   for   end   of   file.   • Each   record   is   in   the   form   of   comma-separated   values.   • There   is   a   new-line   character   at   the   end   of   each   record,   i.e.,   only   one   record   per   line.      
  
The   program   responds   to   two   commands:       :Q       Exits   the   program       :P Displays   the   contents   of   the   database  

Sample   data  
  
Kyle N. Jones,123 Any Street,Raleigh,NC,27615,25000 Eileen Maria Garces,915 Oak Circle,Plano,TX,75074,65000

Assume   that   employee   records   will   always   be   entered   using   the   format   described   above,   i.e.,   name,address,city,state,zip,salary. Note   that   individual   fields   may   contain  
  
spaces.   You   may   also   assume   that   all   of   the   fields   will   contain   data,   i.e.,   it   is   not   necessary   to   handle   missing   fields.  
  
Implementation  
Your   program   must   be   structured   using   multiple   functions,   in   addition   to   main,   as   follows:  
  
void parse_data(char * buffer, struct employee * employee); void get_next_field(char * buffer, char * field); void print_employee_db(int total_employees, struct employee employees[]); void print_employee(struct employee employee);
  
1. The   parse_data   function   parses   a   line   of   data   and   stores   the   contents   in   an   employee   struct.   Both   fields   are   passed-in   by   reference.  
  
2. The   get_next_field   function   reads   the   next   data   field   in   the   input   and   stores   its   contents       in   a   string   (character   array).   Both   fields   are   passed-in   by   reference.  
  
3. The   print_employee_db   function   displays   the   contents   of   the   employee   database   on   the   console.  
  
4. The   print_employee   function   displays   the   contents   of   one   employee   record   on   the   console.  
  
The   number   of   employees   is   not   known   in   advance   and   your   program   cannot   ask   the   user   how   many.   The   program   must   continue   processing   employee   records   until   the   user   enters   “:Q”   to   quit   the   program   or   the   end   of   file   is   detected   in   the   input.  
  
Output
The   program’s   output   must   be   formatted   exactly   as   in   the   examples   shown   below.   It   is   recommended   that   you   use   the   following   formatting   strings,   where   appropriate:  
  
"Enter employee data [:Q to exit, :P to show database]:\n" "Done. Good bye!\n" "\nCurrent Employee Database: \n" "\n\n"

"\nEmployee Record:\n----------\n\tName: %s\n" "\tStreet Address: %s \n" "\tCity: %s \n" "\tState: %s \n" "\tZip: %s \n" "\tSalary: $%.2f \n----------\n"   
  
Some   sample   runs   are   provided   below.   User   input   is   in   bold   typeface.  
  
Sample   #1  
  
Enter employee data [:Q to exit]: :Q Good bye!
  
Sample   #2  
  
Enter employee data [:Q to exit, :P to show database]: Kyle N. Jones,123 Any Street,Raleigh,NC,27615,25000 Enter employee data [:Q to exit, :P to show database]: :P

Current Employee Database:

Employee Record: ---------- Name: Kyle N. Jones Street Address: 123 Any Street City: Raleigh State: NC Zip: 27615 Salary: $25000.00 ----------


Enter employee data [:Q to exit, :P to show database]: :Q Done. Good bye!
  
Sample   #3  
  
Enter employee data [:Q to exit, :P to show database]: Kyle N. Jones,123 Any Street,Raleigh,NC,27615,25000 Enter employee data [:Q to exit, :P to show database]: Eileen Maria Garces,915 Oak Circle,Plano,TX,75074,65000 Enter employee data [:Q to exit, :P to show database]: :P

Current Employee Database:

Employee Record: ---------- Name: Kyle N. Jones Street Address: 123 Any Street City: Raleigh State: NC Zip: 27615 Salary: $25000.00 ----------

  

Employee Record: ---------- Name: Eileen Maria Garces Street Address: 915 Oak Circle City: Plano State: TX Zip: 75074 Salary: $65000.00 ----------


Enter employee data [:Q to exit, :P to show database]: :Q Done. Good bye!

Answer 1

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<conio.h>

struct Employee
{
char name[60];
struct Address
{
char street[49];
char city[29];
char state[2];
char zip[5];
}address;
float salary;
};

struct Employee employee[50];

void get_next_field(char * buffer, char * field)
{
sscanf(buffer, "%[^,]", field);
}

void parse_data(char * buffer, struct Employee * emp)
{
char sal[10];
  
get_next_field(buffer, emp->name);
buffer = strstr(buffer, ",") + 1;
get_next_field(buffer, emp->address.street);
buffer = strstr(buffer, ",") + 1;
get_next_field(buffer, emp->address.city);
buffer = strstr(buffer, ",") + 1;
get_next_field(buffer, emp->address.state);
buffer = strstr(buffer, ",") + 1;
get_next_field(buffer, emp->address.zip);
buffer = strstr(buffer, ",") + 1;
get_next_field(buffer, sal);
  
emp->salary = atof(sal);
}

void print_employee(struct Employee emp)
{
printf("%s ",emp.name);
printf("%s ",emp.address.street);
printf("%s ",emp.address.city);
printf("%s ",emp.address.state);
printf("%s ",emp.address.zip);
printf("%f \n",emp.salary);
}

void print_employee_db(int n, struct Employee employees[])
{
int i;
  
printf("\n******** Employees Data **********\n\n");
printf("\n-----------------------------------------");
printf("\nName\t\tStreet\t\tcity\tstate\tzip\tsalary\n");
printf("\n-----------------------------------------");
  
for(i=0; i<n; i++)
{
printf("\n");
print_employee(employee[i]);
}
  
printf("\n-----------------------------------------");
}

int main()
{
FILE *f;
int i, n = 2;
  
char buffer[150];
char ch;
do{
  
printf("\nEnter employee data [:Q to exit, :P to show database]:");
scanf("%c", &ch);
  
fflush(stdin);
  
switch(ch)
{
case 'Q':
case 'q': printf("Q Good bye! ");
exit(0);
  
case 'P':
case 'p':
f = fopen("file.txt", "r");
if(f==NULL)
{
printf("File cannot be open\n");
getch();
return 1;
}   
  
for(i=0; i<n; i++){
//canf(f,"%[^\n]", buffer);
fgets(buffer, 150, f);
parse_data(buffer, &employee[i]);
}
  
print_employee_db(n, employee);
  
fclose(f);
  
break;
default: f = fopen("file.txt", "a");
if(f==NULL)
{
printf("File cannot be open\n");
getch();
return 1;
}
  
gets(buffer);
  
fprintf(f, "%s \n", buffer);
n++;
fclose(f);
}
}while(1);
  
fclose(f);
  
getch();
return 0;
}

Output:

Enter employee data [:Q to exit, :P to show database]:p

******** Employees Data **********

-----------------------------------------
Name Street city state zip salary

-----------------------------------------
Kyle N. Jones 123 Any Street Raleigh NC27615 27615 25000.000000

Eileen Maria Garces 915 Oak Circle Plano TX75074 75074 65000.000000

-----------------------------------------
Enter employee data [:Q to exit, :P to show database]: