Pt | Cu2+ (aq) | Cu+ (aq) || Fe2+ (aq) | Fe3+ (aq)| Pt
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Consider the following electrochemical cell: Pt | Cu2+ (aq) | Cu+ (aq) || Fe2+ (aq) |...
For the electrochemical cell, Fe(s)| Fe2+ (aq)|| Cu2+ (aq)| Cu+ (aq) | Pt(s), determine the equlibrium constant (Keq) at 25°C for the reaction that occurs.
Consider an electrochemical cell based on the following cell diagram: Pt1 Cut(aq), Cu2+ (aq) || C12(), CI (aq) | Pt Given that the standard cell emf is 1.20V and that the standard reduction potential of chlorine is 1.36 V, what is the standard reduction potential E*(Cu?+/Cut)? A) 1.01V B) 1.06 V C) 0.16 V D) 2.56 V E) -0.16 V
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0.12 M |Fe2 (0.0012 M) Fe(s) E2 =-0.440 V Efe/Fe = 0.339 V Cu2t/Cu Is the electrochemical cell spontaneous or not spontaneous Ecell V as written at 25 °C? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2(0.0060 M), Sn4+(0.14 M) Fe3+(0.13 M), Fe2+(0.0056 M) Pt(s)...
Consider the following cell: Pt(s) | Fe3+ (aq). Fe2(aq) | CIF (aq) C12(e) Pt(s) If the standard reduction potentials of the Fe3+/Fe2+ and Cl2/Cl" couples are +0.77 and +1.36 V, respectively, calculate the value of Efor the given cell. +1.00 V O +1.77 v +0.59 V +2.13 V +0.95 V
What is the cell potential of a cell containing: A Cu electrode in 1.0M Cu2+ A Pt electrode in a solution of 1.0M Fe2+ and 1.0M Fe3+. A salt bridge
7.50 Consider the following cell. Pt Cu2+, Cu+ Fe2+, Fe3+ | Pt (a) What is the cell reaction? (b) What is the standard electro- motive force of the cell at 298.15 K? (c) Calculate Ar Gº for the cell reaction from the standard electromotive force. (d) Calcu- late ArGº for the cell reaction using the AfGº values for the ions in Table C.2. (e) Calculate ArGº for the cell reaction using the AfHº values and Sº values in Table C.2.
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
QUESTION 27 Calculate Ecell under non-standard conditions for the following electrochemical cell: Pt(s)| FeCl2 (aq, 0.150 M), FeCl3 (aq, 0.050 M) || Cl2 (9, 1 atm), NaCl (aq, 0.075 M) | Pt (s) -1.60 V 0.72 v 0.69 V -1.79 V 0.62 V none of these
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
Consider the following electrochemical cell: Al (s) I Al3+ (aq) (1.00 M) II Cu2+ (aq) (0.0020 M) I Cu (s) where Cu2+ aq + 2e- -> Cu (s) +0.34 V and Al3+ aq + 3e- -> Al (s) -1.66 V Calculate the standard cell potential for the given cell, calculate the cell potential for the given cell, and sketch the electrochemical cell using two beakers and labeling the electrodes, the cathode, the anode, the direction of electron flow in the...