The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...

Question

Question

The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...

The equilibrium constant, K_c, for the following reaction is 1.31×10^-2 at 700 K.

NH₄I(s) (forward/reverse arrow)NH₃(g) + HI(g)

1. Calculate K_c at this temperature for the following reaction:

NH₃(g) + HI(g) (forward/reverse arrow)NH₄I(s)

K_c =

2. The equilibrium constant, K_c, for the following reaction is 2.03 at 677 K.

2NH₃(g) (forward/reverse arrow)N₂(g) + 3H₂(g)

Calculate K_c at this temperature for:

N₂(g) + 3H₂(g) (forward/reverse arrow)2NH₃(g)

K_c =

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

If the reaction is reversed the new equilibrium constant becomes inverse of the original one.

K_c^' = 1/K_c

Add a comment

Answer 2

Similar Homework Help Questions

The equilibrium constant, Kc, for the following reaction is 5.89×10-4 at 635 K. NH4I(s)<-->NH3(g) + HI(g)...

The equilibrium constant, Kc, for the following reaction is 5.89×10-4 at 635 K. NH4I(s)<-->NH3(g) + HI(g) Calculate Kc at this temperature for the following reaction: NH3(g) + HI(g) <-->NH4I(s) Kc=?
The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) <-->NH3(g) +...

The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) <-->NH3(g) + HI(g) Calculate the equilibrium concentration of HI when 0.354 moles of NH4I(s) are introduced into a 1.00 L vessel at 673 K. [HI]= ____M
The equilibrium constant, K, for the following reaction is 9.25×10-3 at 692 K. NH4I(s) NH3(g) +...

The equilibrium constant, K, for the following reaction is 9.25×10-3 at 692 K. NH4I(s) NH3(g) + HI(g) An equilibrium mixture in a 12.1 L container at 692 K contains 0.348 mol NH4I(s), 0.118 M NH3 and 7.84×10-2 M HI. What will be the concentrations of the two gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 5.98 L? [NH3] = M [HI] = M

The equilibrium constant, K, for the following reaction is 6.76×10-3 at 685 K. NH4I(s) NH3(g) +...

The equilibrium constant, K, for the following reaction is 6.76×10-3 at 685 K. NH4I(s) NH3(g) + HI(g) An equilibrium mixture in a 11.7 L container at 685 K contains 0.229 mol NH4I(s), 0.101 M NH3 and 6.69×10-2 M HI. What will be the concentrations of the two gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 6.27 L?
The equilibrium constant, K, for the following reaction is 7.00×10-5 at 673 K. NH4I(s)----> NH3(g) +...

The equilibrium constant, K, for the following reaction is 7.00×10-5 at 673 K. NH4I(s)----> NH3(g) + HI(g) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 673 K contains 0.388 mol NH4I, 8.37×10-3 M NH3 and 8.37×10-3 M HI. If the concentration of NH3(g) is suddenly increased to 1.46×10-2 M, what will be the concentrations of the two gases once equilibrium has been reestablished? [NH3] = ______ M [HI] = _______ M
The equilibrium constant, K, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) -->NH3(g) +...

The equilibrium constant, K, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) -->NH3(g) + HI(g) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 673 K contains 0.335 mol NH4I, 8.37×10-3 M NH3 and 8.37×10-3 M HI. If the concentration of NH3(g) is suddenly increased to 1.28×10-2 M, what will be the concentrations of the two gases once equilibrium has been reestablished?

Question The equilibrium constant, Kc, for the following reaction is 3.72 at 701 K. 2NH3(gN2(g) +...

Question The equilibrium constant, Kc, for the following reaction is 3.72 at 701 K. 2NH3(gN2(g) + 3H2(g) Calculate Kc at this temperature for the following reaction: 1/2N2(g) +3/2H2(g) NH3( Kc
-The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) +...

-The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibrium concentration of HCl when 0.452 moles of NH4Cl(s) are introduced into a 1.00 L vessel at 548 K. [HCl] = _________M -The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K. H2(g) + I2(g) 2 HI (g) Calculate the equilibrium concentrations of reactants and product when 0.380 moles of H2and 0.380 moles of I2are introduced into a 1.00...
The equilibrium constant, Kc, for the following reaction is 5.0110 at 514 K. NH4Cl(s) =NH3(g) +...

The equilibrium constant, Kc, for the following reaction is 5.0110 at 514 K. NH4Cl(s) =NH3(g) + HCl(g) Calculate Ke at this temperature for the following reaction: NH3(g) + HCI(g) = NH,Cl(s) K. = ) Submit Answer Retry Entire Group 1 more group attempt remaining

The equilibrium constant, Kc , for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g)...

The equilibrium constant, Kc , for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) If an equilibrium mixture of the three compounds in a 5.41 L container at 548 K contains 1.17 mol of NH4Cl(s) and 0.350 mol of NH3, the number of moles of HCl present is ( ) moles. The equilibrium constant, Kc , for the following reaction is 1.80×10-4 at 298 K. NH4HS(s) NH3(g) + H2S(g) If an equilibrium mixture of the three...

The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...

Homework Answers

Add Answer to:
The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...

Post as a guest

Earn Coins

The equilibrium constant, Kc, for the following reaction is 5.89×10-4 at 635 K. NH4I(s)<-->NH3(g) + HI(g)...

The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) <-->NH3(g) +...

The equilibrium constant, K, for the following reaction is 9.25×10-3 at 692 K. NH4I(s) NH3(g) +...

The equilibrium constant, K, for the following reaction is 6.76×10-3 at 685 K. NH4I(s) NH3(g) +...

The equilibrium constant, K, for the following reaction is 7.00×10-5 at 673 K. NH4I(s)----> NH3(g) +...

The equilibrium constant, K, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) -->NH3(g) +...

Question The equilibrium constant, Kc, for the following reaction is 3.72 at 701 K. 2NH3(gN2(g) +...

-The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) +...

The equilibrium constant, Kc, for the following reaction is 5.0110 at 514 K. NH4Cl(s) =NH3(g) +...

The equilibrium constant, Kc , for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g)...

The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...

Homework Answers

Add Answer to: The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...

Post as a guest

Earn Coins

Add Answer to:
The equilibrium constant, Kc, for the following reaction is 1.31×10-2 at 700 K. NH4I(s) (forward/reverse arrow)NH3(g)...