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The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) <-->NH3(g) +...

The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K.

NH4I(s) <-->NH3(g) + HI(g)

Calculate the equilibrium concentration of HI when 0.354 moles of NH4I(s) are introduced into a 1.00 L vessel at 673 K.

[HI]= ____M

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Answer #1

NH41(s) - NH3(g) & HILG) 0.354 mol How 1.00L. - 2 +x 0.354-a [WHyl] = is 1 because et soted . Ke= [NH₃] [nl] INH41] ke= x² 7x

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