a production process produces 4% defective parts. a sample of six parts from the production process...
Homework Answers
Probability of a part being defective (p)= 4% = 0.04
Probability of a part not being defective (q) = 1-0.04 = 0.96
Sample size = 6
This is a case of binomial distribution.
Probability that the sample contains more than one defective parts=
1 - ( Probability of 0 defective parts + Probability of 1 defective part)
= 1 - (6C0 * (0.04)0 * (0.96)6 + 6C1 * (0.04)1 * (0.94)5 )
= 1 - 0.9784
= 0.02155
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