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Chefs: Assume the mean number of taste buds from the general population is 10,000 with a...

Chefs: Assume the mean number of taste buds from the general population is 10,000 with a standard deviation of 950. You take a sample of 10 top chefs and find the mean number of taste buds is 10,900. Assume that the number of taste buds in top chefs is a normally distributed variable and assume the standard deviation is the same as for the general population.
(a) What is the point estimate for the mean number of taste buds for all top chefs?
? taste buds

(b) What is the critical value of z (denoted zα/2) for a 95% confidence interval? Use the value from the table or, if using software, round to 2 decimal places.
zα/2 =  

(c) What is the margin of error (E) for the mean number of taste buds for top chefs in a 95% confidence interval? Round your answer to the nearest whole number.
E =  taste buds

(d) Construct the 95% confidence interval for the mean number of taste buds for all top chefs. Round your answers to the nearest whole number.
< μ <  

(e) Based on your answer to part (d), are you 95% confident that top chefs have, on average, more taste buds than the general population and why?

Yes, because the population mean of 10,000 is below the upper limit of the confidence interval for the mean for top chefs.

No, because the general population mean of 10,000 is below the lower limit of the confidence interval for the mean for top chefs.    

Yes, because the general population mean of 10,000 is below the lower limit of the confidence interval for the mean for top chefs.

No, because the population mean of 10,000 is below the upper limit of the confidence interval for the mean for top chefs.
(f) Why were we able to use the methods of this chapter despite such a small sample?

Because we are assuming the number of taste buds in top chefs is a normally distributed variable.

Because the number of taste buds represents a discrete variable.    

Because the sample mean is sufficiently large.Because σ is greater than 100.

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