Chefs: Assume the mean number of taste buds
from the general population is 10,000 with a standard deviation of
950. You take a sample of 10 top chefs and find the mean number of
taste buds is 10,900. Assume that the number of taste buds in top
chefs is a normally distributed variable and assume the standard
deviation is the same as for the general population.
(a) What is the point estimate for the mean number of taste
buds for all top chefs?
? taste buds
(b) What is the critical value of z (denoted
zα/2) for a 95% confidence interval?
Use the value from the table or, if using software, round to 2
decimal places.
zα/2 =
(c) What is the margin of error (E) for the mean
number of taste buds for top chefs in a 95% confidence interval?
Round your answer to the nearest whole number.
E = taste buds
(d) Construct the 95% confidence interval for the mean
number of taste buds for all top chefs. Round your answers to the
nearest whole number.
< μ <
(e) Based on your answer to part (d), are you 95% confident
that top chefs have, on average, more taste buds than the general
population and why?
Yes, because the population mean of 10,000 is below the upper limit of the confidence interval for the mean for top chefs.
No, because the general population mean of 10,000 is below the lower limit of the confidence interval for the mean for top chefs.
Yes, because the general population mean of 10,000 is below the lower limit of the confidence interval for the mean for top chefs.
No, because the population mean of 10,000 is below the upper
limit of the confidence interval for the mean for top chefs.
(f) Why were we able to use the methods of this chapter
despite such a small sample?
Because we are assuming the number of taste buds in top chefs is a normally distributed variable.
Because the number of taste buds represents a discrete variable.
Because the sample mean is sufficiently large.Because σ is greater than 100.
Chefs: Assume the mean number of taste buds from the general population is 10,000 with a...
Assume the mean number of taste buds from the general population is 10,000 with a standard deviation of 850. You take a sample of 10 top chefs and find the mean number of taste buds is 10,900. Assume that the number of taste buds in top chefs is a normally distributed variable and assume the standard deviation is the same as for the general population. (a) What is the point estimate for the mean number of taste buds for all...
Calculate an approximate 68% confidence interval for the population mean salaries of male employees, based on the following sample data: from a sample of 144 male employees, the sample mean salaries is $500. Assume the population standard deviation is $144. Assume the distribution of salaries is normally distributed. Enter your answer in the format (lower, upper) where the "lower" is the lower confidence limit and the "upper" is the upper confidence limit. Round each numerical input to the nearest integer.
Thirty-one small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 43.5cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the upper, and lower limit? (Round your answers to one decimal place.) (b) Find a 95% confidence interval for the population mean annual number of reported larceny...
Assuming the random variable X is normally distributed, compute the upper and lower limit of the 95% confidence interval for the population mean if a random sample of size n=11 produces a sample mean of 43 and sample standard deviation of 6.20. Lower limit = , Upper limit = Round to two decimals.
Thirty-two small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 40.5 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit upper limit margin of error (b) Find a 95% confidence interval for the...
Thirty-three small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 40.5 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit upper limit margin of error (b) Find a 95% confidence interval for the...
Thirty-two small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that o is known to be 42.1 cases per year. (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.) lower limit 11.8 upper limit margin of error (b) Find a 95% confidence interval for...
Construct a 99% confidence interval to estimate the population mean using the data below. X = 46 o = 12 n42 With 99% confidence, when n = 42 the population mean is between a lower limit of (Round to two decimal places as needed.) and an upper limit of Construct a 95% confidence interval to estimate the population mean with X = 102 and o = 25 for the following sample sizes. a) n = 32 b) n = 45...
Construct a 95% confidence interval to estimate the population mean with x overbar =118 and sigma =32 for the following sample sizes. a) n = 32 b) n = 43 c) n = 65 a) With 95% confidence, when n=32, the population mean is between the lower limit of ___ and the upper limit of ___. (Round to two decimal places as needed.) b) With 95% confidence, when n=43, the population mean is between the lower limit of...
Construct a 95% confidence interval to estimate the population mean with x=101 and σ=27 for the following sample sizes. a) n equals= 3030 b) n equals= 4343 c) n equals= 6464 a) With 95% confidence, when n=30, the population mean is between the lower limit of and the upper limit of. (Round to two decimal places as needed.) b) With95% confidence, when n=43, the population mean is between the lower limit of and the upper limit of. (Round to two...