Question

Need some help on this Python Problem called "unique words" the text.txt file can be any .txt file with words in it.

Write a program that opens a specified text file and then displays the number of unique words in the text file after stripping all the white spaces, comma, and the punctuation marks and list of all the unique words found in the file. The list should be sorted in alphabetical order. The program should handle the ‘file not found’ error. Store each word as an element of list. Be sure not to use the function ‘set’ in the program.

Sample outputs

Enter the name of the input file:

Error: File not found!

Another run….

Enter the name of the input file: text.txt

There are 171 unique words in the text.

These are the unique words in the text sorted in alphabetical order:

1840

2,000

According

Arabia

China

Whose

Wheels

Answer 1

Note: Please uprate and please comment for any further help.

Code Snapshot:

Code:

import re
def main():
    list = []
    file=input("Enter the name of the input file: ")
    try:
        f = open(file)
    except IOError:
        print('Error: File not found!')
    else:
        with f:
            fileData=f.readlines()
        for x in fileData:
            x=re.sub(r'([^\w\s]|_)+(?=\s|$)', '', x) #to remove extra special character
            words=x.split(" ")
            for word in words:
                word=word.strip() #removing spaces
                if word: #checking if word is not empty
                    if word not in list:
                        list.append(word)      
      
        list.sort() # sorting the list
        print("There are "+str(len(list))+" unique words in the text.") #printing the length
        print("These are the unique words in the text sorted in alphabetical order:")
        for word in list:
            print(word) #printing word by word

main()

Output: