Probability of 2 or less successes out of 8 trials if the probability of success is 0.75.
Solution:
n = 8
p = 0.75
q = 1 – p = 0.25
We have to find P(X≤2)
P(X≤2) = P(X=0) + P(X=1) + P(X=2)
P(X=x) = nCx*p^x*q^(n – x)
P(X=0) = 8C0*0.75^0*0.25^8 = 0.000015
P(X=1) = 8C1*0.75^1*0.25^7 = 0.000366
P(X=2) = 8C2*0.75^2*0.25^6 = 0.003845
P(X≤2) = 0.000015 + 0.000366 + 0.003845
P(X≤2) = 0.004226
Required probability = 0.004226
Probability of 2 or less successes out of 8 trials if the probability of success is...
For a Binomial random variable, the probability of exactly zero successes out of two trials equals 0.0289. What is the associated probability of "success," p?
For a Binomial random variable, the probability of exactly zero successes out of two trials equals 0.0289. What is the associated probability of "success," p? a) 0.9711 b) 0.8300 c) 0.1700 d) 0.0008
Consider a binomial distribution with n = 10 trials and the probability of success on a single trial p = 0.75. (a) Is the distribution skewed left, skewed right, or symmetric? (b) Compute the expected number of successes in 10 trials. (c) Given the high probability of success p on a single trial, would you expect P(r ≤ 2) to be very high or very low? Explain. (d) Given the high probability of success p on a single trial, would...
5A A Bernoulli Trials experiment consists of 4 trials, with a 4/5 probability of success on each trial. What is the probability of at least 1 success and at least 1 failure? What is the probability of 2 successes, given at least 1 success? What is the probability of at least 2 successes, given at least 2 failures? Enter your answers as whole numbers or fractions in lowest terms.
Assume that a procedure yields a binomial distribution with 2 trials and a probability of success of 0.70. Use a binomial probability table to find the probability that the number of successes is exactly 0. The probability that the number of successes is exactly 0 is: ?
For each Bernoulli process, find the expected number of successes: 1. Number of trials =10, Probability of success =0.6 2. Number of trials =210, Probability of success =1/10. 3. Number of trials =43, Probability of success =0.3. 4. Number of trials =23, Probability of failure =0.8. 5. Number of trials =59, Probability of failure =2/7.
Problem 1 Consider a sequence of n+m independent Bernoulli trials with probability of success p in each trial. Let N be the number of successes in the first n trials and let M be the number of successes in the remaining m trials. (a) Find the joint PMF of N and M, and the marginal PMFs of N and AM (b) Find the PMF for the total number of successes in the n +m trials. Problem 1 Consider a sequence...
5c A Bernoulli Trials experiment has p=8/23 probability of success on each trial What is the expected number of successes in five trials? What is the expected number of failures in 14 trials? What is the expected number of failures in 46 trials?
Calculate each binomial probability: (a) Fewer than 5 successes in 10 trials with a 15 percent chance of success. (Round your answer to 4 decimal places.) Probability (b) At least 1 successe in 9 trials with a 20 percent chance of success. (Round your answer to 4 decimal places.) Probability (c) At most 11 successes in 19 trials with a 70 percent chance of success. (Round your answer to 4 decimal places.) Probability ...
Given the number of trials and the probability of success, determine the probability indicated: n = 15, p = 0.4, find P(4 successes) n = 12, p = 0.2, find P(2 failures) n = 20, p = 0.05, find P(at least 3 successes)