For a Binomial random variable, the probability of exactly zero successes out of two trials equals 0.0289. What is the associated probability of "success," p?
P[X=0] = C(2,0)*(P)0 * (1-P)2 = 0.0289
Therefore,
(1-P)2 = 0.0289
1-2P+P2 = 0.0289
P =1.17 or P=0.83
P= 1.17 is not possible
Therefore, p=0.83
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For a Binomial random variable, the probability of exactly zero successes out of two trials equals...
For a Binomial random variable, the probability of exactly zero successes out of two trials equals 0.0289. What is the associated probability of "success," p? a) 0.9711 b) 0.8300 c) 0.1700 d) 0.0008
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