1) n = 35
p = 0.5
Expected value = n * p = 35 * 0.5 = 17.5
2) n = 10
p = 0.54
P(X = 4) = 10C4 * 0.544 * (1 - 0.54)10-4 = 0.169
3) n = 10
p = 0.56
P(X = 4) = 10C4 * 0.564 *(1 - 0.56)10-4 = 0.150
4) n = 10
p = 0.33
P(X = 4) = 10C4 * 0.334 * (1 - 0.33)10-4 = 0.225
QUESTION 1 Consider a random variable with a binomial distribution, with 35 trials and probability of...
For a Binomial random variable, the probability of exactly zero successes out of two trials equals 0.0289. What is the associated probability of "success," p?
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For a Binomial random variable, the probability of exactly zero successes out of two trials equals 0.0289. What is the associated probability of "success," p? a) 0.9711 b) 0.8300 c) 0.1700 d) 0.0008
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A random variable follows a binomial distribution with a probability of success equal to 0.64. For a sample size of n=9, find the values below. a. the probability of exactly 3 successes b. the probability of 6 or more successes c. the probability of exactly 9 successes d. the expected value of the random variable
5.2 Assume that a procedure yields a binomial distribution with N equals=5 trials and a probability of success of p equals=0.200.20. Use a binomial probability table to find the probability that the number of successes x is exactly 2. LOADING... P(2) = ___________ (Round to three decimal places as needed.)
In the binomial probability distribution, let the number of trials be n = 3, and let the probability of success be p = 0.3634. Use a calculator to compute the following. (a) The probability of two successes. (Round your answer to three decimal places.) (b) The probability of three successes. (Round your answer to three decimal places.) (c) The probability of two or three successes. (Round your answer to three decimal places.)
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places. P(X≥7), n=10, p=0.5