How long will it take money to double if it is invested at the following rates? (A) 4.8% compounded monthly (B) 10.5% compounded monthly
Answer A.
Amount invested = $1
Desired sum = $2
Annual interest rate = 4.80%
Monthly interest rate = 0.40% (4.80% / 12)
Let it will take n months to double the investment
Amount invested * (1 + Monthly interest rate)^Period = Desired
sum
$1 * 1.004^n = $2
1.004^n = 2
n * ln(1.004) = ln(2)
n = 173.63
Number of months = 173.63
Number of years = 173.63 / 12
Number of years = 14.47 years
Answer B.
Amount invested = $1
Desired sum = $2
Annual interest rate = 10.50%
Monthly interest rate = 0.875% (10.50% / 12)
Let it will take n months to double the investment
Amount invested * (1 + Monthly interest rate)^Period = Desired
sum
$1 * 1.00875^n = $2
1.00875^n = 2
n * ln(1.00875) = ln(2)
n = 79.56
Number of months = 79.56
Number of years = 79.56 / 12
Number of years = 6.63 years
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