Calculate the amount of 1.50 M Na2CO3 needed to react completely with 25.0 mL of 0.500...

Question

Question

Calculate the amount of 1.50 M Na2CO3 needed to react completely with 25.0 mL of 0.500 M CaCl2

Answer 1

Answer #1

given

1.50 M Na2CO3

25.0 mL of 0.500 M CaCl2

we know that

M1V1 = M2V2

1.50 M * V1 = 0.500 M * 25.0 mL

==> V1 = 8.3 mL

so amount required is 8.3 mL

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Answer 2

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