Question

What mass Na2CO3 will completely react with 150 mL of 0.15 M HNO3?

a) write the balanced equation

b) construct the pathway of how you would approach the problem.

c) write out the calculation

d) calculate

Answer 1

a) the reactants are Na2CO3 and the HNO3 the balanced equation is as follows

Na₂CO₃ + 2 HNO₃ --------------------> 2 NaNO₃ + H₂O + CO₂

b) first find the moles of HNO3 ------- based on the balanced the equation find the moles of Na2CO3 ----- from moles of Na2CO3 calculate the mass from the moles and the molar mass

c) moles HNO3 = molarity * volume in liters => 0.15 M * 0.150 L => 0.0225 moles

1 mol Na2CO3 ------------------> 2 mol HNO3

? ---------------------------------> 0.0225 mol

=> 0.0225 * 1 / 2 => 0.01125 moles

i.e moles of Na2CO3 = 0.01125 moles

d) mass of Na2CO3 = 0.00125 moles * 105.9888 g/mol => 1.192374 grams

answer => 1.2 grams of Na2CO3