Question

Consider the page table shown below for a system with 16-bit virtual and physical addresses and with 4096-byte pages. All numbers below are given in hexadecimal. (A dash for a page frame indicates that the page is not in memory.)

Page Number	Physical Frame Number
0	-
1	2
2	C
3	A
4	-
5	4
6	3
7	-
8	B
9	0

How many bits are in the offset part of the address?

How many hex digits long is the offset part?

Answer 1

16 bit Virtual and Physical addess

We know that Virtual address is divided into virtual page number + Offset
& Physical address is divided into physical page number + Offset


Since page size is 4096 bytes = 2¹² that means 12 bits are part of offset
16 = 4 + 12


How many bits are in the offset part of the address?
12
How many hex digits long is the offset part?
3 , As 1 Hex = 4 binary digit => 12/4 = 3 hex digit


Thanks, PLEASE COMMENT if there is any concern.