Be sure to answer all parts. Find the pH and the volume (mL) of 0.447 M HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5H5N, Kb = 1.7 × 10−9). Volume = mL HNO3
pH =
Be sure to answer all parts. Find the pH and the volume (mL) of 0.447 M...
Be sure to answer all parts. Find the pH and the volume (mL) of 0.487 M HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5HzN, Kb = 1.7 x 10-9). Volume = mL HNO3 pH-
Be sure to answer all parts. Find the pH of the two equivalence points and the volume (mL) of 0.427 M HNO3 needed to reach them in the titration of 0.188 L of 0.250 M ethylenediamine (H2NCH2CH2NH2). First equivalent point: mL HNO3 pH- Second equivalent point: mL HNO3 pH
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.0822 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2. Volume: mL KOH pH =
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.125 M HCl needed to reach the equivalence point in the titration of 65.5 mL of 0.234 M NH3. Volume = mL HCl pH =
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.0702 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO,. Volume: mL KOH pH =
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.0302 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2.
Be sure to answer all parts. Find the pH of the equivalence point and the volume (mL) of 0.200 M HCl needed to reach the equivalence point in the titration of 65.5 mL of 0.234 M NH3.\ \ ]
Be sure to answer all parts Find the pH of the two equivalence points and the volume (mL) of 0.0538 M KOH needed to reach them in the titration of 17.3 mL of 0.130 MH2CO3. First equivalent point Second equivalent point mL KOH mL KOH pH
Please show all work. Be sure to answer all parts. Find the pH of the two equivalence points and the volume (mL) of 0.0496 M KOH needed to reach them in the titration of 17.3 mL of 0.130 M H2CO3. Second equivalent point First equivalent point mL KOH mL KOH pH= pH =
1))))Weak Base Titration: At the Equivalence Point a))A 11.30 mL solution of 2.47 M pyridine (C5H5N, a weak base) is titrated to the equivalence point with 22.4 mL of HNO3. What is the pH at the equivalence point? Kb for pyridine is 1.7 X 10-9. b))))Click on all of the dominant species that you would expect to find in solution at the equivalence point. Do not include H3O+ and OH-ions unless they are coming from another source other than the...