Question

The earth is 8 light minutes from the sun and the speed of light is 3x10...

The earth is 8 light minutes from the sun and the speed of light is 3x10 to the power of 8 m/s. Lets assume that the earths orbit is exactly circular. It's mass is 5.972x10 to the power of 24kg.
Using the values given above, determine the magnitude of the gravitational force that the sun exerts on the earth

0 0
Add a comment Improve this question Transcribed image text
Answer #1

distance between earth and sun

r = 8 * 60* 3* 10^8 = 1.44* 10^11 m

force

F = GMm / r^2 = 6.67* 10^-11* 5.98* 10^24* 5.972* 10^24 / (1.44* 10^11)^2

F = 1.154* 10^21 N

=====

Comment before rate in case any doubt, will reply for sure.. goodluck

Add a comment
Know the answer?
Add Answer to:
The earth is 8 light minutes from the sun and the speed of light is 3x10...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 01. (i) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, (ii)...

    01. (i) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, (ii) And the net force exerted on the Earth. iii) What exerts this force on the Earth? Assume that the Earth's orbit is a circle of radius 1.5 X 10' m (iv) Calculate the Gravitational Force between the Earth and the Sun. (v) Compare the Gravitational Force to that net force from section (ii) above. Given that F mg (vi) Calculate the acceleration due to...

  • e alignment of the sun, earth, and orce FSM that the sun exerts on the moon...

    e alignment of the sun, earth, and orce FSM that the sun exerts on the moon is per- 5.98 × 1024 kg, 8. The distances shown in the drawing are rawing (not to scale) shows on pendicular to the force FeM that the earth exerts on the m are: mass of sun = 1.99 × 1030 kg, mass of earth = mass of moon = 7.35 × 1022 k SM-1.30 × 10 11 m and rEM-3.85 × 108 m. Determine...

  • A satellite of mass 5580 kg orbits the earth and has a period of 6670 s....

    A satellite of mass 5580 kg orbits the earth and has a period of 6670 s. A. Determine the radius of its circular orbit B. Determine the magnitude of the earths gravitational force on the satellite C. Determine the altitude of the satellite

  • 8. A cosmic-ray proton traveling at half the speed of light (speed of light c 3x10...

    8. A cosmic-ray proton traveling at half the speed of light (speed of light c 3x10 m/sec) is heading directly towards the center of the Earth in the plane of the Earth's equator. Assume that the Earth's magnetic field is uniform over the planet's equatorial plan with a magnitude of IBI-50.0x10-6 T, extending out a distance d 1.3x107m from the surface of the Earth. Assume that the field is zero at greater distances. Will the cosmic-ray proton hit the Earth?...

  • A satellite of Earth is moving in a circular orbit with Earth at its center, at...

    A satellite of Earth is moving in a circular orbit with Earth at its center, at a constant speed of 2.00 km/s. a.) How high is the satellite above the surface of the Earth? b.) How long does it take for the satellite to complete one revolution? Helpful info (but not all of it is relevant!): universal gravitational constant G is = 6.674 x 10^-11 m^3/kg s^2 (units may also be expressed as N m^2/kg^2) Mass of Sun = 1.989...

  • 2. Support the space shuttle is in orbit about the earth at 400 km above its...

    2. Support the space shuttle is in orbit about the earth at 400 km above its surface. Determine the orbital speed and the orbital period of the space shuttle. 3.calculate the minimum velocity (escape speed) a spacecraft must have to escape the gravitational force of the planet earth. Mearth=5.972 x 10^24kg 4. Calculate the schwarzschild radius of a black hole with the mass of the sun.Mearth=5.972 x 10^24kg

  • Q1. (i) (ii) (iii) Calculate the centripetal acceleration of the Earth in its orbit around the...

    Q1. (i) (ii) (iii) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, And the net force exerted on the Earth. What exerts this force on the Earth? Assume that the Earth's orbit is a circle of radius 1.5 X 101 m (iv) (v) Calculate the Gravitational Force between the Earth and the Sun Compare the Gravitational Force to that net force from section (ii) above.

  • An object of mass m moves at a constant speed v in a circular path of radius r.

    An object of mass m moves at a constant speed v in a circular path of radius r. The force required to produce the centripetal component of acceleration is called the centripetal force and is given by F=mv2/r. Newton's Law of Universal Gravitation is given by F=GMm/d2, where d is the distance between the centers of the two bodies of masses M and m, and G is a gravitational constant. The speed required for circular motion is v= √(GM/r). Use the...

  • 1 What is the Earth's orbital speed as it orbits the Sun. Take the Earth/Sun distance...

    1 What is the Earth's orbital speed as it orbits the Sun. Take the Earth/Sun distance to be 93 million miles (taking the Earth's orbit to be circular), the mass of the Earth to be 5.97 X 102 kg and the mass of the Sun to be 1.987 X 10*0 kg. Solve this problem using Newton's 2nd law directly 2. A 55.7 kg mass is lifted (at a constant velocity) from the ground to a vertical height of 1275 m....

  • the sun is 1.50 x 108 km from earth, and the speed of light is 3.00 x 108 m/s. how many minutes...

    the sun is 1.50 x 108 km from earth, and the speed of light is 3.00 x 108 m/s. how many minutes elapse as light travels from the sun toearth?please show work

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT