Question

At takeoff a commercial jet has a 55.0 m/s speed. Its tires have a diameter of 0.700 m. (a) At how many rpm are the tires rotating? Incorrect: Your answer is incorrect. rpm (b) What is the centripetal acceleration at the edge of the tire? Incorrect: Your answer is incorrect. m/s2 (c) With what force must a determined 10-15 kg bacterium cling to the rim? Incorrect: Your answer is incorrect. N (d) Take the ratio of this force to the bacterium's weight. Incorrect: Your answer is incorrect. (force from part (c) / bacterium's weight)

Answer 1

a)

angular velocity

w = v/r = 55 / 0.7 = 78.571 rad/s

w = 78.571* 60 / 2pi = 750.68 rpm

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b)centripetal acceleration

ac= r w^2 =0.7* 78.571^2

ac = 4321.43 m/s^2

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c)

F = ma = 4.321* 10^-12 N

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d)

ratio = a /g = 441

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