You have a magnet that is 2.3cm in diameter and 9cm long. At the north pole...
You have a magnet that is 2.3cm in diameter and 9cm long. At the north pole of this magnet, the magnetic field is 0.09T. You want to see if you can construct a solenoid with the same dimensions as the bar magnet with the same strength. If you constructed the solenoid out of 18-gauge wire (diameter 1.02mm), how many turns would it take when passing 2.2A through it to create the same magnetic field? Does this seem like a reasonable solenoid? Explain.
Homework Answers
Magnetic field, B = u0 NI/L
0.09 = (4 pi x 10^-7) x N x 2.2/0.09
Number of turns, N = 2932
For such a small solenoid, these number of turns are not possible. So, this solenoid is not reasonable
Comment in case any doubt please rate my answer....
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