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A bowling ball weighing 71.2 N is swinging like a pendulum at the end of a...

A bowling ball weighing 71.2 N is swinging like a pendulum at the end of a 3.8 m rope. As the ball swings through its lowest point, its speed is measured at 4.2 m/s. What is the magnitude and direction of the acceleration of the ball at this point?

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Answer #1

Here,

at the lowest point

there will be no tangential acceleration

the only acceleration is centripetal

hence , for the total acceleration

total acceleration = v^2/L

total acceleration = 4.2^2/3.8

total acceleration = 4.64 m/s^2

the acceleration is towards the center of circle

the magnitude of acceleration is 4.64 m/s^2 in upwards direction

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