Question

Use a "while" loop to take character input and display the total number of vowels entered with separate count for each of the vowels.  

Following is a sample run of the program:

------------------------------------------------------------------------------------
Enter a word. Enter to digit to mark the end of word.
television
0

Number of a's: 0
Number of e's: 2
Number of i's: 2

Use a "while" loop to take character input and display the total number of vowels entered with separate count for each of the vowels.  

Following is a sample run of the program:

------------------------------------------------------------------------------------
Enter a word. Enter to digit to mark the end of word.
television
0

Number of a's: 0
Number of e's: 2
Number of i's: 2
Number of o's: 1
Number of u's: 0
--------------------------------
Process exited after 11.26 seconds with return value 0
Press any key to continue . . .

Number of o's: 1
Number of u's: 0
--------------------------------
Process exited after 11.26 seconds with return value 0
Press any key to continue . . .

**Basic beginners code**

Answer 1

Hello, here is the completed code you wanted. Every important statement is explained using comments. Please check and let me know if you have any doubts. Thanks.

CODE

In C++

#include<iostream>

using namespace std;

int main()
{
   //variables
   char characters[100];
   int i=0,count_a=0,count_e=0,count_i=0,count_o=0,count_u=0;
  
   //prompt for word
   cout<<"Enter a word. Enter to digit to mark the end of word."<<endl;
  
   //while loop
   while(true)
   {
       //inputs characters
       cin>>characters[i];
      
       //if digit exits the loop
       if(characters[i]>='0' && characters[i]<='9')
           break;
       //counting number of a
       if(characters[i]=='a')
           count_a++;
       //counting number of e
       if(characters[i]=='e')
           count_e++;
       //counting number of i
       if(characters[i]=='i')
           count_i++;
       //counting number of o
       if(characters[i]=='o')
           count_o++;
       //counting number of u
       if(characters[i]=='u')
           count_u++;
   }
   //printing outputs
   cout<<"Number of a's: "<<count_a<<endl;
   cout<<"Number of e's: "<<count_e<<endl;
   cout<<"Number of i's: "<<count_i<<endl;
   cout<<"Number of o's: "<<count_o<<endl;
   cout<<"Number of u's: "<<count_u<<endl;
   return 0;
}

In C

#include<stdio.h>

int main()
{
   //variables
   char characters[100];
   int i=0,count_a=0,count_e=0,count_i=0,count_o=0,count_u=0;
  
   //prompt for word
   printf("Enter a word. Enter to digit to mark the end of word.\n");
  
   //while loop
   while(1)
   {
       //inputs characters
       scanf("%c",&characters[i]);
      
       //if digit exits the loop
       if(characters[i]>='0' && characters[i]<='9')
           break;
       //counting number of a
       if(characters[i]=='a')
           count_a++;
       //counting number of e
       if(characters[i]=='e')
           count_e++;
       //counting number of i
       if(characters[i]=='i')
           count_i++;
       //counting number of o
       if(characters[i]=='o')
           count_o++;
       //counting number of u
       if(characters[i]=='u')
           count_u++;
   }
   //printing outputs
   printf("Number of a's: %d\n",count_a);
   printf("Number of e's: %d\n",count_e);
   printf("Number of i's: %d\n",count_i);
   printf("Number of o's: %d\n",count_o);
   printf("Number of u's: %d\n",count_u);
   return 0;
}

OUTPUT

CODE SCREEN SHOT

C++

C