The pressure inside a gas bottle is 3080 kPa when the temperature is 24.8 °C. What will be the pressure inside the bottle, if 33.9 percent of the gas is released and the temperature of the gas drops to 7.2 °C?
we have
pv = nRT
then
P1 V1 / n1 R T1 = P2 V2 / n2 R T2
P2 = ( n2 T2 P1 / n1 T1 )
= ( 100-33.9)*(273+7.2) *3080 kPa / ( 100*(273+24.8))
P2 =1915.559 kPa answer
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