A 10 kg mass with an initial velocity of 6 i m/s collides and sticks to a 5 kg mass with an initial velocity of - 5 j m/s. Find the direction (in degrees) of the final velocity of the two masses with respect to the direction of the x axis. (Note: take your calculated angle as positive.)
here,
mass of object 1 , m1 = 10 kg
initial velocity of 1 , u1 = 6 i m/s
mass of object 2 , m2 = 5 kg
initial velocity of 2 , u2 = - 5 j m/s
let the final velocity be v
using conservation of momentum
m1 * u1 + m2 * u2 = (m1 + m2) * v
10 * 6 i - 5 * 5 j = ( 10 + 5) * v
solving for v
v = 4 i m/s - 1.67 j m/s
the direction of final velocity with respect to direction of x-axis , theta = arctan((-1.67)/4)
theta = 22.7 degree
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