Question

2. Two steel balls are colliding elastically. Ball 1 has a mass of 1.20 kg and is moving 3.00 m/s at an angle of 45 degrees measured from the positive X-axis before the collision. Ball 2 has a mass of 1.50 kg and is moving 2.50 m/s at an angle of 60 degrees above the negative X- axis before the collision. Assume the balls hit squarely without a glancing blow so the balls can roll in the direction calculated normally. Draw a diagram. A. Find the initial momentum vector for each ball in using i-hat and j-hat vectors. B. Find the momentum vector of the center of mass of the system. C. Find the final velocity vector for each ball. D. Find the impulse delivered to each ball.

Answer 1

PAGE 73m. m = 12kg e 66 Tuso 2-5-C05601 3 00145 X Here 4,=3m16 m = 1.2kg U2 =2.5 m/s 202 = 15kg Before Collisim. momenten in x direction. Prz = mu, cs4s - mu Cal60 = 1.2x3 nous' - 1.5X2.560360 5 3.6 x < - 3:75x1 = 2.55 - 1.88 = 0.67 kg mpe I by = m, 4, Sinus & M₂, Singo = 1.2X3X3 + 1.5 X 2.5 *17 = 2.55+ 3.25 = 5.8 kg wps. momenten veeter of the centreg mass of the system. Let v= very = (36345-2.5666072 - + (3 sinust 2.5 sin66) - V-10.872+ (4-2912 = h 38 milya - (M + MV Les comme (1.541:2) 4.38 = 183 kg myse

DATE PAGE wing Conservating a momentin if after Collision balls roll with velocity v. 6 me, Casus-22, U, CS 60 = (mitm) UGSO mu, sinust m. 4 Sinbo - cm, tm ) e sind - 2.7 2.7 from 1 2.545-1.875 = 2.7 vaso - Vaso = 0.67 -0.248 = 0.25 G from vand- 5.8 = 2.15 - from ③ & 4 th O= 0.66 and O= 33.42 - पछV3.. 5 impuse I- Change in momenten AP Tox (la xdirection) { £ - P) = (0:675-0-67)= 0.005 (581-58) = 0.005 P = cm, +2012 juoso = (1.5+1.2) X0.25 = 0.675 Pig cina diret) (Pr-lo) = Pf = mtm Jusind = (1.5+1:2)X2.15 = 3.81 REDMI NOTE 8 PRO 64 MP QUAD CAMERA