In a study conducted by biologists Sokal and Hunter, the wing lengths of houseflies were found to be approximately normally distributed, with a mean wing length of 45.5 mm, and a standard deviation of 3.92 mm.
A housefly is randomly selected, find the probability that its wing length is less than 45 mm.
Solution :
Given that,
mean = = 45.5
standard deviation = = 3.92
P(X<45 ) = P[(X- ) / < (45-45.5) / 3.92]
= P(z < -0.13)
Using z table
=0.4483
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