Question

ONE_TEN = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Demonstrate replacing values with the larger of their neighbors and demonstrate shifting to the right replacing the furthermost element with the first element in the list.
data = list(ONE_TEN)
def replaceNeighbors(data):
for i in range(len(data)):
if data[i] < data[i+1]:
data[i] == data[i+1]
replaceNeighbors(data)
print("After replacing with neighbors: ", data)

data = list(ONE_TEN)
def shiftRight(data):
data= data[-1] + dta[:-1]
shiftRight(data)
print("After shifting right: ", data)

im having trouble with these two functions can some please help me with these codes?

Answer 1

Please let me know if anything is required. Please follow the indentation as shown in the code screenshot.

Code screenshot:

Sample output:

Copyable code: Please find the bold code for the differences between your code and written by me.

ONE_TEN = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
data = list(ONE_TEN)
def replaceNeighbors(data):
'''
as we are checking with the current element with next element then we should use len(data)-1
to avoid index out of bound exception
'''
for i in range(1,len(data)-1):
if data[i] < data[i+1]:
'''
NOTE : to assign we have to use = not ==
== means comparing
'''
data[i] = data[i+1]
return data

data=replaceNeighbors(data)

print("After replacing with neighbors: ", data)

data = list(ONE_TEN)

def shiftRight(data):
'''
we have to save the element into the other variable before assigning another value
to avoid loss of our current element value
'''
temp=data[-1]
data=data[0:len(data)-1]
data=[temp]+data
return data

data=shiftRight(data)
print("After shifting right: ", data)