Question

In a popular painkiller medicine, it is advertised there is 500 mg of the active ingredient per pill. The amount of active ingredient per pill follows a normal distribution with a mean of 506 mg and a standard deviation of 2 mg. What is the probability that a single pill of the painkiller contains less than 500 mg of active ingredient? (Use a table or technology. Round your answer to four decimal places.)

Answer 1

Solution :

Given that,

mean = = 506

standard deviation = = 2

P(X<500 ) = P[(X- ) / < (500-506) /2 ]

= P(z <-3 )

Using z table

probability=0.0013