Question

Create a program in java to find the 3rd largest and 3rd smallest element in a single dimension array (Input 10 elements) after arranging them in ascending and descending order separately.

Answer 1

import java.util.Scanner;

public class LargestSmallest {
   public static void sortAsc(int arr[], int n) {
       int i, j, temp;
       // outer loop to travel through the all elements
       for (i = 0; i < n - 1; i++) {
           // inner loop to compare the outer loop elements
           for (j = 0; j < n - i - 1; j++)
               // if element at j< than j+1 than swap both
               if (arr[j] > arr[j + 1]) {
                   // swap logic
                   temp = arr[j];
                   arr[j] = arr[j + 1];
                   arr[j + 1] = temp;
               }
       }

   }

   public static void sortDsc(int arr[], int n) {
       int i, j, temp;
       // outer loop to travel through the all elements
       for (i = 0; i < n - 1; i++) {
           // inner loop to compare the outer loop elements
           for (j = 0; j < n - i - 1; j++)
               // if element at j< than j+1 than swap both
               if (arr[j] < arr[j + 1]) {
                   // swap logic
                   temp = arr[j];
                   arr[j] = arr[j + 1];
                   arr[j + 1] = temp;
               }
       }

   }

   public static void main(String[] args) {
       int arr[] = new int[10];
       System.out.println("Enter 10 elements: ");
       Scanner sc = new Scanner(System.in);
       for (int i = 0; i < 10; i++)
           arr[i] = sc.nextInt();
       sortDsc(arr, arr.length);
       System.out.println("3rd largest element: " + arr[2]);
       sortAsc(arr, arr.length);
       System.out.println("3rd smallest element: " + arr[2]);
       sc.close();

   }
}

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