Question

Q2. Write programs in Java as follows: a. Get user input for the size and eleme innut for the size and elements of arr10 and arr2( which are of integer and double type nain(). Find the second smallest and second largest element in both arrays in sort and sort20) after arranging them in increasing order simultaneously. Find the difference of elements found in sort1() and sort2() separately and display them in main() ...8 Marks

Answer 1

The program to take input two array and arrange them in increasing order and finding the difference of 2nd largest and 2nd smallest number is as follows :

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import java.util.*; //Import to declare Scanner variable to take user input
public class SecondSmallLarge
{

  
   public static void main(String[] args) //Main Function Starts Here
   {
       Scanner sc = new Scanner(System.in); //Declaring Scanner Class to take input form user
       System.out.println("Enter the Size of Array of Integers");//Prompting user to provide the size of integer array
       int size1 = sc.nextInt(); //Taking input the size of array of integers
       System.out.println("Enter "+size1+" elements of Integer Array");//Prompting user to provide the elements of integer array
       int arr1[] = new int[size1]; //Declaring integer array arr1 of size given by user
       for(int i=0;i<size1;i++)
       {
           arr1[i]=sc.nextInt(); //Taking input the elements of integer array from user
       }
       System.out.println("Enter the Size of Array of real numbers");//Prompting user to provide the size of array of type double
       int size2 = sc.nextInt(); //Taking input the size of array of integers
       System.out.println("Enter "+size2+" elements of Array of real numbers");//Prompting user to provide the elements of array of type double
       double arr2[] = new double[size2];//Declaring array arr2 of type double and size as given by user
       for(int i=0;i<size2;i++)
       {
           arr2[i]=sc.nextDouble(); //Taking input the elements of array of type double from user
       }
int diff1 = sort1(size1,arr1);//Calling method sort1 and storing the returned value from the in variable diff1
double diff2=sort2(size2,arr2);//Calling method sort2 and storing the returned value from the method in variable diff2
//Below line will print the difference of 2nd largest and 2nd smallest Integers in Integer array
System.out.println("The difference of 2nd largest and 2nd smallest Integers in Integer array is : "+diff1);
//Below line will print the difference of 2nd largest and 2nd smallest numbers in array of type double
System.out.println("The difference of 2nd largest and 2nd smallest numbers in array of type double is : "+diff2);
   }
//Method Sort1() takes the size and array of integers as input and arranges
//the array in increasing order and finds the 2nd largest and 2nd smallest
//numbers in the array and returns the difference of the numbers to the main method
//Here we have used selection sort to sort the array
   public static int sort1(int n,int arr[]) //sort1() method starts here
{
   int min=0; //variable min is declared which will hold the index of minimum number in every pass
   //selection sort logic starts here
      for(int i=0;i<n-1;i++)
   {
       min = i; //variable min will hold the index pointed by variable i
       for(int j=i+1;j<n;j++)
       {
           //This loop scans the array and finds the smallest element and
           //the index of smallest element is assigned to vairable min
           if(arr[min]>arr[j])
               min=j;
       }
       //Here swapping is done to the elements pointed by i and min
       //After this swapping smallest element searched by inner loop is
       //places in the index pointed by i
       int temp = arr[min];
       arr[min]=arr[i];
       arr[i]=temp;
   }
   //The next for will display the array arranged in increasing order
   System.out.println("Arranged array in Increasing Order is as follows ");
   for(int i=0;i<n;i++)
   System.out.println(arr[i]);
   //Finding the 2nd smallest element in arranged array
   int secondsmall = arr[1];
   //Finding the 2nd largest element in arranged array
   int secondlarge = arr[n-2];
   //Printing the 2nd smallest element in the array
   System.out.println("Second smallest Number in Integer Array is : "+secondsmall);
   //Printing the 2nd largest element in the array
   System.out.println("Second largest Number in Integer Array is : "+secondlarge);
      //The following statement will return the difference of
   //Second largest and 2nd Smallest number to the main method
   return (secondlarge-secondsmall);
}
  
   //Method Sort2() takes the size and array of type double as input and arranges
   //the array in increasing order and finds the 2nd largest and 2nd smallest
   //numbers in the array and returns the difference of the numbers to the main method
   //Here we have used selection sort to sort the array
public static double sort2(int n,double arr[])
{
   int min=0; //variable min is declared which will hold the index of minimum number in every pass
   //selection sort logic starts here
   for(int i=0;i<n-1;i++)
   {
       min = i;//variable min will hold the index pointed by variable i
       for(int j=i+1;j<n;j++)
       {          
           //This loop scans the array and finds the smallest element and
           //the index of smallest element is assigned to variable min
           if(arr[min]>arr[j])
               min=j;
       }
       //Here swapping is done to the elements pointed by i and min
       //After this swapping smallest element searched by inner loop is places in the index pointed by i
       double temp = arr[min];
       arr[min]=arr[i];
       arr[i]=temp;
   }  
   //The next for will display the array arranged in increasing order
   System.out.println("Arranged array in Increasing Order is as follows ");
   for(int i=0;i<n;i++)
   System.out.println(arr[i]);
   //Finding the 2nd smallest element in arranged array
   double secondsmall = arr[1];
   //Finding the 2nd largest element in arranged array
   double secondlarge = arr[n-2];
   //Printing the 2nd smallest element in the array
   System.out.println("Second smallest Real Number is : "+secondsmall);
   //Printing the 2nd largest element in the array
   System.out.println("Second largest Real Number is : "+secondlarge);
      //The following return statement will return the difference of
   //Second largest and 2nd Smallest number to the main method
   return (secondlarge-secondsmall);
}
}

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The Screen shot of the program is as follows

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The output of the program is as follows

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Enter the Size of Array of Integers
6
Enter 6 elements of Integer Array
34
54
12
33
7
45
Enter the Size of Array of real numbers
5
Enter 5 elements of Array of real numbers
23.5
66.2
8.76
45.7
33
Arranged array in Increasing Order is as follows
7
12
33
34
45
54
Second smallest Number in Integer Array is : 12
Second largest Number in Integer Array is : 45
Arranged array in Increasing Order is as follows
8.76
23.5
33.0
45.7
66.2
Second smallest Real Number is : 23.5
Second largest Real Number is : 45.7
The difference of 2nd largest and 2nd smallest Integers in Integer array is : 33
The difference of 2nd largest and 2nd smallest numbers in array of type double is : 22.200000000000003
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The screen shot of the output is as follows

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