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a coin collector has 10 identical silver coins and 6 identical gold coins. in how many...

a coin collector has 10 identical silver coins and 6 identical gold coins. in how many ways can he place these 16 coins in a row if no two gold coins are placed next to each other?

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Answer #1

We need no two gold coins are together hence we placed all silver coins at 1-1 place gap between them.

So, there will be total 11 spaces to fit gold coins

It will be like: _S_S_S_S_S_S_S_S_S_S_

There are total _ shows the place where we can put gold coins

Total favorable ways = C(11, 6) =

So, total 462 ways are there so that no two gold coins are together.

Please comment if any doubt. Thank you.

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