Solution(a)
Total No. Of sample space = 3×2×2= 12
Sample space with probability is
(Gold, Gold, Gold) =(2×4×3/(10×10×10))= 0.024
(Gold, Silver, Gold)=(2×6×3)/1000 = 36/1000= 0.036
(Gold, Gold, Copper)=(2×4×7)/1000=0.056
(Gold, silver, copper)=(2×6×7)/1000=84/1000=0.084
(Silver, Gold, Gold)=(5*4*3)/1000=0.060
(Silver, Gold, Copper)=(5×4×7)/1000=0.14
(Silver,Silver, Gold)=(5×6×3)/1000=0.09
(Silver, silver, copper)=(5×6×7)/1000=0.21
(Copper, Gold,Gold)=(3×4×3)/1000=0.036
(Copper, Gold, Copper)=(3×4×7)/1000=0.084
(Copper, silver,Gold)=(3×6×3)/1000=0.054
(Copper, silver, copper) = (3×6×7)/1000= 0.126
Solution(b)
P(X= No gold coin selected) = 0.126+0.21= 0.336
P(1 Gold coin selected) = 0.054+0.084+0.09+0.14+0.084= 0.452
P(2Gold coin selexted)= 0.036+0.06+0.056+0.036=0.188
P(3 Gold coin)= 0.024
Three hats each contain ten coins. Hat 1 contains two gold coins, five silver coins and...
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