3 fair coins, 4 2-headed coins
probability of getting a fair coin = P(F) = 3/(3+4) = 3/7
probability of getting a two headed coin P(UF) = 4/7
(a)
probability of getting head P(H)
= P(F).P(H|F) + P(UF).P(H|UF)
= 3/7.1/2 + 4/7.1
= 11/14
(b)
P(F|H) = P(F).P(H|F)/P(H)
= 3/7.1/2.14/11
= 3/11
(c)
P(UF|H) = P(UF).P(H|UF)/P(H)
= 4/7.1.14/11
= 8/11
(d)
P(F|T) = 1 coz two headed coin doesnt have tail
(e)
possible cases are -
2 fair coins
one fair one two headed coin
2 two headed coins
So probability will be 1/3
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