Question

Suppose you again have seven coins in your pocket, 1 quarter, 4 dimes, and 2 pennies....

Suppose you again have seven coins in your pocket, 1 quarter, 4 dimes, and 2 pennies. Again, you randomly extract one coin from your pocket, look at the coin, and then return that coin to your pocket. You then randomly extract a second coin from your pocket and look at that coin. If the events are again P1 = "first pick was a penny" and D2 = "Second pick was a dime," what is the probability of picking these two coins? Show how you arrived at your conclusion (using probabilities).

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Answer #1

Probability (P1) = Number of pennies/Total number of coins = 2/7

Probability (D2) = Number of dimes/Total number of coins remaining after the first coin is replaced = 4/7

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