For a randomly selected envelope probability of receiving money is
P(0) = 3/10
P(5) = 5/10
P(10) = 2/10
3 envelopes are selected at random, without replacement
P(0) as maximum = P(0) in 1st *P(0) in 2nd *p(0) in 3rd
= (3/10)^3
= 0.009
P(5 maximum) = P(0)*P(0)*P(5) + P(0)*P(5)*P(0) + P(5)*P(0)*P(0) + P(0)*P(5)*P(5) + P(5)*P(5)*P(0) + P(5)*P(0)*P(5) + P(5)*P(5)*P(5)
= (3/10)^2*(5/10) * 3 + (3/10)*(5/10)^2* 3 + (5/10)^3
= 0.485
P(10 maximum) = 1 - (0.009+ 0.485) = 0.506
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