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A box contains ten sealed envelopes numbered 1,..., 10. The first six contain no money, the next two each contains $5, and th

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Answer #1

for P(m=0) =P(all three envelop contains no money) =(6/10)3 =0.216

P(m=5) =P(all from 8 envelop which contains at most $5)-P(all three with 0 money) =(8/10)3-0.216=0.296

{m=10)=1-(8/10)3 =0.488

m 0 5 10
p(m) 0.216 0.296 0.488
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