As SnCl2 is in excess and HgCl2 is limited (5g) and amount of products formed depends on the amount of limited reagent available .
How much mercury metal cab be obtained in the reaction between tin (ii) chloride and mercury...
i need B & C Consider the following reaction between mercury(II) chloride and oxalate ion. 2 HgCl_2(ag) + C_2O_4^2-(ag) rightarrow 2 Cl^- (aq) + 2 CO_2(g) + Hg_2Cl_2(s) The initial rate of this reaction was determined for several concentrations of HgCl_2 and C_2O_4^2-, and the following rate data were obtained for the rate of disappearance of C_2O_4^2-. a) What is the rate law for this reaction? (b) What is the value of the rate constant? (c) What is the reaction...
Consider the following reaction between mercury(II) chloride and oxalate ion. 2 HgCl_2(ag) + C_2O_4^2-(ag) rightarrow 2 Cl^- (aq) + 2 CO_2(g) + Hg_2Cl_2(s) The initial rate of this reaction was determined for several concentrations of HgCl_2 and C_2O_4^2-, and the following rate data were obtained for the rate of disappearance of C_2O_4^2-. a) What is the rate law for this reaction? (b) What is the value of the rate constant? (c) What is the reaction rate when the concentration of...
Irom metal reacts with chlorine gas giving iron(II) chloride. The balanced chemical equationfor this reaction is: 2 Fe(s) 3 C12(g) 2 FeCl3(s) 75.5 g FeCl, can be produced from 26.0 g of iron and excess Clh. If only 21.3 g of FeCly is obtained, what is the percent yield?
In an acidic solution, permanganate ion reacts with tin(II) ion to give manganese(II) lon and tin(IV) ion. (a) Enter a balanced net ionic equation for the reaction (include physical states in your answer). 2+ 2+ 4+ 2MnO& (aq) + 5Sn (aq)+16H (aq)-2Mn (aq) + 5Sn (ag)+8H O) Save & Close Undo Select Erase Help 7 8 (aq) (g) () (s) 4 5 6 e + E NONE 1 2 C F NR Na Mg Al Si P CI K Ca...
If a solution containing 81.921 g of mercury(II) perchlorate is allowed to react completely with a solution containing 13.180 g of sodium sulfide, how many grams of solid precipitate will form? precipitate: How many grams of the reactant in excess will remain after the reaction? excess reactant:
on 8 of 9 > If a solution containing 27.79 g of mercury(II) nitrate is allowed to react completely with a solution containing 7.410 g of sodium sulfate according to the equation below. Hg(NO3)2(aq) + Na, SO, (aq) — 2NaNO3(aq) + Hg50 (9) How many grams of solid precipitate will be formed? mass: How many grams of the reactant in excess will remain after the reaction? mass:
estion 9 of 24 > If a solution containing 72.957 g of mercury(II) chlorate is allowed to react completely with a solution containing 10.872 g of sodium sulfide, how many grams of solid precipitate will form? precipitate: How many grams of the reactant in excess will remain after the reaction? excess reactant: Question Source: MRG - General Chemistry | Publisher: University Scien about us Careers privacy policy terms of ntact us help MacBook Pro
If a solution containing 51.406 g of mercury(II) perchlorate is allowed to react completely with a solution containing 13.180 g of sodium sulfate, (A) how many grams of solid precipitate will be formed? (B) How many grams of the reactant in excess will remain after the reaction?
If a solution containing 57 20 g of mercury(II) nitrate is allowed to react completely with a solution containing 9.718 g of sodium sulfide, how many grams of solid precipitate will be formed? How many grams of the reactant in excess will remain after the reaction?
71. The reaction between Copper (II) Chloride and Sodium Nitrate is a simple double replacement reaction. a) Write and balance the reaction between Copper (II) Chloride and Sodium Nitrate b) If 15.0 grams of Copper (II) Chloride react with 20.0 grams of Sodium Nitrate, what is the theoretical yield for Sodium Chloride? A d oi mlbo2 d tal do oA oholdoony2o no d s What is the limiting reagent for this reaction? c) nWnoitulo e chododes sis o bo ei...