A satellite is orbiting the Earth at a distance of 50’000 km above sea level. (a)...
A satellite is orbiting the Earth at a distance of 50’000 km above sea level. (a) What is the gravitational acceleration at this altitude? (15 pts) (b) What is the speed of the satellite along its circular orbit? (5 pts) Earth’s radius: RE = 6370 km Earth’s mass: ME = 5.973 × 1024 kg Universal Gravitational constant: G = 6.674 × 10−11 m3kg−1 s −2
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A satellite is orbiting the Earth at a distance of
50’000 km above sea level. (a)...
Using Newton’s law of gravitation, find the centripetal acceleration of a satellite orbiting the Earth at...
Using Newton’s law of gravitation, find the centripetal acceleration of a satellite orbiting the Earth at a distance of R = 12×106 m. What is the angular velocity of that satellite? What is the period of motion? Earth’s mass: ME = 5.973×1024 kg Universal Gravitational constant: G = 6.674×10−11 m3kg−1s−2.
A 270 kg satellite is orbiting on a circular orbit 6180 km above the Earth's surface....
A 270 kg satellite is orbiting on a circular orbit 6180 km above the Earth's surface. Determine the speed of the satellite. (The mass of the Earth is 5.97×1024 kg, and the radius of the Earth is 6370 km.)
A 180 kg satellite is orbiting on a circular orbit 6355 km above the Earth's surface. Determine the speed of the satell...
A 180 kg satellite is orbiting on a circular orbit 6355 km above the Earth's surface. Determine the speed of the satellite. (The mass of the Earth is 5.97x1024 kg, and the radius of the Earth is 6370 km.) Submit Answer Tries 0/12
A 507 kg satellite is in a circular orbit at an altitude of 754 km above...
A 507 kg satellite is in a circular orbit at an altitude of 754 km above a planet’s surface. This planet is similar to our Earth. Because of air friction, the satellite eventually is brought to the Earth’s surface, and it hits the Earth with a speed of 3 km/s. The radius of the planet is 7 × 106 m and its mass is 8 × 1024 kg. The gravitational constant is 6.67259 × 10−11 N m2 /kg2. How much...
Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit h...
Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit has an orbital period of exactly one day. Assume a spherical Earth, and use the following constants (taken from Vallado, David A., Fundamentals of Astrodynamics and Applications, 2nd ed. 2001) Gravitational constant: G 6.673 x 10-20 km Radius of the Earth: Re = 6378.137 km 1024 kg Mass of the Earth: Me = 5.9733328 x Round your final answer to four...
A satellite is in orbit around Earth at a height of 120 km above Earth’s surface....
A satellite is in orbit around Earth at a height of 120 km above Earth’s surface. Find the orbital speed of the satellite. (Mass of the earth is 6*1024 kg and the radius of Earth is 6371 km)
A satellite m = 500 kg orbits the earth at a distance d = 218 km,...
A satellite m = 500 kg orbits the earth at a distance d = 218 km, above the surface of the planet. The radius of the earth is re = 6.38 × 106 m and the gravitational constant G = 6.67 × 10-11 N m2/kg2 and the Earth's mass is me = 5.98 × 1024 kg. What is the speed of the satellite in m/s?
12.104. A satellite describes a circular orbit at an altitude of 19 110 km above the...
12.104. A satellite describes a circular orbit at an altitude of 19 110 km above the surface of the earth. Determine (a) the increase in speed required at point A for the satellite to achieve the escape velocity and enter a parabolic orbit, (b) the decrease in speed required at point A for the satellite to enter an elliptic orbit with a minimum altitude of 6370 km, (c) the eccentricity e of the elliptic orbit. R = 6370 km 19...
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x...
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication...
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication around the world. (You may consider that the mass of the satellite is m, mass of the earth is M(6x1024 kg), center-to-center distance between the satellite and the earth is r, radius of the earth is R(6.4×106 m), and the universal gravitational constant G = 6.67x10-11 N.m2/kg2.) Satellite Earth Applying newton's 2nd law, write an equation describing the circular motion of the satellite. (4...
A 180 kg satellite is orbiting on a circular orbit 6355 km above the Earth's surface. Determine the speed of the satellite. (The mass of the Earth is 5.97x1024 kg, and the radius of the Earth is 6370 km.) Submit Answer Tries 0/12
Derive the "Clarke radius", the altitude above the surface of the Earth where a satellite in a circular orbit has an orbital period of exactly one day. Assume a spherical Earth, and use the following constants (taken from Vallado, David A., Fundamentals of Astrodynamics and Applications, 2nd ed. 2001) Gravitational constant: G 6.673 x 10-20 km Radius of the Earth: Re = 6378.137 km 1024 kg Mass of the Earth: Me = 5.9733328 x Round your final answer to four...
12.104. A satellite describes a circular orbit at an altitude of 19 110 km above the surface of the earth. Determine (a) the increase in speed required at point A for the satellite to achieve the escape velocity and enter a parabolic orbit, (b) the decrease in speed required at point A for the satellite to enter an elliptic orbit with a minimum altitude of 6370 km, (c) the eccentricity e of the elliptic orbit. R = 6370 km 19...
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication around the world. (You may consider that the mass of the satellite is m, mass of the earth is M(6x1024 kg), center-to-center distance between the satellite and the earth is r, radius of the earth is R(6.4×106 m), and the universal gravitational constant G = 6.67x10-11 N.m2/kg2.) Satellite Earth Applying newton's 2nd law, write an equation describing the circular motion of the satellite. (4...
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