A municipal wastewater flow of 20,000 m3/day has an influent bsCOD = 152 g/m3 and an...
A municipal wastewater flow of 20,000 m3/day has an influent bsCOD = 152 g/m3 and an influent nbVSS = 30 g/m3. The WWTP effluent has 6 g bsCOD/m3 when the MLVSS is maintained at 2500 g/m3. Referring to Table 7-8 in Metcalf and Eddy, you may assume:
k = 5 g bsCOD/(g VSS•day),
KS = 40 g bsCOD/m3
Y = 0.4 g VSS/g bsCOD,
b = 0.1 g VSS/(g VSS•day)
Also, fd = 0.1 g VSS/g biomass VSS depleted by decay. Determine the following parameters for a complete-mix activated-sludge system that removes organic matter only: What is hydraulic retention time (τ) [=] hours?
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A municipal wastewater flow of 20,000 m3/day has an influent
bsCOD = 152 g/m3 and an...
A complete-mix activated sludge system is used to treat municipal wastewater after primary sedime...
A complete-mix activated sludge system is used to treat municipal wastewater after primary sedimentation at 20 °C with MLVSS concentration of 2000 g/m3. The discharge standard for soluble BOD, concentration in the effluent is 0.5 g/m. The characteristics of the primary influent are: flow Q -2000 m'/d, soluble BOD -200 g/m3, Using these data and the kinetic coefficients in following, determine 1. Theoretical solids retention time (SRT) in unit of days 2. Pk vss in unit of kg VSS/d 3....
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge (kg/d), and the BOD f a completely mixed activated-sludge process by assuming the following: k 4.0 day r-0.55 lb vS...
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge (kg/d), and the BOD f a completely mixed activated-sludge process by assuming the following: k 4.0 day r-0.55 lb vSS/1b BOD, K, 80 mg/l, ks-0.05 day', wastewater flow rate 2.5 mgd, soluble effluent BOD- 15 mgl, soluble influent BOD - 170 mgl, and MLVSS-2200 mg/l, and mean cell residence time -6 days. (15 pts)
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge...
Introduction to environmental Engineering. C David Cooper, Chapter 6 Homework 6.14 For municipal wastewater that receives...
Introduction to environmental Engineering. C David Cooper, Chapter 6 Homework 6.14 For municipal wastewater that receives treatment with the activated sludge process, plot the effluent BOD5 as a function of solids residence time using values of SRT that range from 1 to 20 days. The influent BOD5 concentration is 220 mg/L. Assume the following wastewater characteristics: Variable order kinetics k = 5 mg BOD5/mg VSS-day, Ks = 60 mg BOD5/L, Ymax = 0.6 mg VSS/mg BOD5, Ke = 0.06 day^-1....
Secondary Treatment Based on a plant flow rate of 40 mgd, design an activated sludge, secondary t...
Secondary Treatment Based on a plant flow rate of 40 mgd, design an activated sludge, secondary treatment system with recycle which maintains a MLVSS = 2,000 mg/L in the aeration reactor and has an average Solids Retention Time (SRT)-4 days. The biota kinetic constants are Kinetic Coefficients for the Activated-sludge Process for the Removal of Organic Matter from Domestic Wastewater Endogenous Decay Coefficient- k(d) 0.1 Half-velocity constant- K(s VSS/qVss-da 15 Mg/L bsCOD Max. Specific Substrate Utilization Rate-k 6 G bsCOD/gVSS-da...
6.8 a. Using the variable-order kinetic information from Example 6.8 for a municipal wastewater, ...
6.8 a. Using the variable-order kinetic information from Example 6.8 for a municipal wastewater, determine the effluent BODs concentration for a complete-mix activated sludge facility operated at a five-day solids residence time. b. For a wastewater flow rate of 2 million gallons per day with character- istics of a typical wastewater from Table 6.1, determine the discharge rate of biomass (Ibs/day). in the lagooll lall x biomass Rearranging Eq.(6.37) V X HRT EXAMPLE 6.8 Determine the required volume of an...
Environmental Engineering 3&4 So 3. An activated sludge plant treats 5 MGD and the average influent...
Environmental Engineering 3&4
So 3. An activated sludge plant treats 5 MGD and the average influent BOD is 200 mg/L. The WWTP has 2 aeration basins, each 100 ft x 25 ft x 15 ft deep and 2 final clarifiers with diameters of 20 ft. About 35% of BOD is removed in primary clarifiers. Determine the BOD in the primary effluent, hydraulic retention time, F/M ratio, BOD exiting the aeration basin and mass of solids wasted (1b/d). The operation parameters...
A wastewater flow of 18,000 m3/day is to be treated in a completely mixed activated sludge...
A wastewater flow of 18,000 m3/day is to be treated in a completely mixed activated sludge system at a concentration of 3000 mg/L MLSS (mixed liquor suspended solids). The secondary clarifier is designed to thicken the sludge to 12,000 mg/L. Assuming a growth yield coefficient of 0.5 Kg/Kg, an influent BOD of 100 mg/L with a residence time of 8 days, determine the following: a) The volume of the reactor b) The mass of the solids and the wet volume...
A Tapered aeration-system is used to treat 12,500 m3/d of municipal wastewater. The wastewater has received...
A Tapered aeration-system is used to treat 12,500 m3/d of municipal wastewater. The wastewater has received primary treatment and has a BOD 5 of 140 mg/l and a suspended solids of 125 mg/l. The system is to be operated in the following way: (a) Soluble BOD 5 in effluent 5 mg/l (b) Average solids concentration in the reactor= 2000 mg/l (c) Mean cell- retention time= 10 d. The biological constants have been determined by pilot-plant analysis and are: Y= 0.55...
(30 points) A completely mixed activated sludge system comprised of an aerated reactor and a secondary clarifier with sludge return is going to treat 15,000 m/d of industrial wastewater. Th...
(30 points) A completely mixed activated sludge system comprised of an aerated reactor and a secondary clarifier with sludge return is going to treat 15,000 m/d of industrial wastewater. The primary effluent going to the reactor has a BODs of 1,100 mg/L that must be reduced to 150 mg/L prior to discharge to a municipal sewer. The pilot study was conducted and generated the following results: 3. Mean cell residence time- 5 day, MLSS concentration in the reactor 7.200 mg/L...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...
A complete-mix activated sludge system is used to treat municipal wastewater after primary sedimentation at 20 °C with MLVSS concentration of 2000 g/m3. The discharge standard for soluble BOD, concentration in the effluent is 0.5 g/m. The characteristics of the primary influent are: flow Q -2000 m'/d, soluble BOD -200 g/m3, Using these data and the kinetic coefficients in following, determine 1. Theoretical solids retention time (SRT) in unit of days 2. Pk vss in unit of kg VSS/d 3....
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge (kg/d), and the BOD f a completely mixed activated-sludge process by assuming the following: k 4.0 day r-0.55 lb vSS/1b BOD, K, 80 mg/l, ks-0.05 day', wastewater flow rate 2.5 mgd, soluble effluent BOD- 15 mgl, soluble influent BOD - 170 mgl, and MLVSS-2200 mg/l, and mean cell residence time -6 days. (15 pts)
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge...
Secondary Treatment Based on a plant flow rate of 40 mgd, design an activated sludge, secondary treatment system with recycle which maintains a MLVSS = 2,000 mg/L in the aeration reactor and has an average Solids Retention Time (SRT)-4 days. The biota kinetic constants are Kinetic Coefficients for the Activated-sludge Process for the Removal of Organic Matter from Domestic Wastewater Endogenous Decay Coefficient- k(d) 0.1 Half-velocity constant- K(s VSS/qVss-da 15 Mg/L bsCOD Max. Specific Substrate Utilization Rate-k 6 G bsCOD/gVSS-da...
6.8 a. Using the variable-order kinetic information from Example 6.8 for a municipal wastewater, determine the effluent BODs concentration for a complete-mix activated sludge facility operated at a five-day solids residence time. b. For a wastewater flow rate of 2 million gallons per day with character- istics of a typical wastewater from Table 6.1, determine the discharge rate of biomass (Ibs/day). in the lagooll lall x biomass Rearranging Eq.(6.37) V X HRT EXAMPLE 6.8 Determine the required volume of an...
Environmental Engineering 3&4
So 3. An activated sludge plant treats 5 MGD and the average influent BOD is 200 mg/L. The WWTP has 2 aeration basins, each 100 ft x 25 ft x 15 ft deep and 2 final clarifiers with diameters of 20 ft. About 35% of BOD is removed in primary clarifiers. Determine the BOD in the primary effluent, hydraulic retention time, F/M ratio, BOD exiting the aeration basin and mass of solids wasted (1b/d). The operation parameters...
A wastewater flow of 18,000 m3/day is to be treated in a completely mixed activated sludge system at a concentration of 3000 mg/L MLSS (mixed liquor suspended solids). The secondary clarifier is designed to thicken the sludge to 12,000 mg/L. Assuming a growth yield coefficient of 0.5 Kg/Kg, an influent BOD of 100 mg/L with a residence time of 8 days, determine the following: a) The volume of the reactor b) The mass of the solids and the wet volume...
(30 points) A completely mixed activated sludge system comprised of an aerated reactor and a secondary clarifier with sludge return is going to treat 15,000 m/d of industrial wastewater. The primary effluent going to the reactor has a BODs of 1,100 mg/L that must be reduced to 150 mg/L prior to discharge to a municipal sewer. The pilot study was conducted and generated the following results: 3. Mean cell residence time- 5 day, MLSS concentration in the reactor 7.200 mg/L...
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