6.8 a. Using the variable-order kinetic information from Example 6.8 for a municipal wastewater, ...
Introduction to environmental Engineering. C David Cooper, Chapter 6 Homework 6.14 For municipal wastewater that receives treatment with the activated sludge process, plot the effluent BOD5 as a function of solids residence time using values of SRT that range from 1 to 20 days. The influent BOD5 concentration is 220 mg/L. Assume the following wastewater characteristics: Variable order kinetics k = 5 mg BOD5/mg VSS-day, Ks = 60 mg BOD5/L, Ymax = 0.6 mg VSS/mg BOD5, Ke = 0.06 day^-1....
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge (kg/d), and the BOD f a completely mixed activated-sludge process by assuming the following: k 4.0 day r-0.55 lb vSS/1b BOD, K, 80 mg/l, ks-0.05 day', wastewater flow rate 2.5 mgd, soluble effluent BOD- 15 mgl, soluble influent BOD - 170 mgl, and MLVSS-2200 mg/l, and mean cell residence time -6 days. (15 pts)
3. Determine the aeration tank volume (mgd), excess biomass in the waste sludge...
A wastewater treatment plant, which serves a population of 300,000 people, receives an average daily volume of 24 million gallons per day (MGD) at an average influent 5-day biochemical oxygen demand concentration of 200 mgBODs/L and an average influent total suspended solids concentration of 220 mgTSS/L. The plant operates a primary sedimentation process that remove 65% of the incoming TSS and 35% of the incoming BOD %. This process is followed by a secondary treatment process before discharge to the...
(30 points) A completely mixed activated sludge system comprised of an aerated reactor and a secondary clarifier with sludge return is going to treat 15,000 m/d of industrial wastewater. The primary effluent going to the reactor has a BODs of 1,100 mg/L that must be reduced to 150 mg/L prior to discharge to a municipal sewer. The pilot study was conducted and generated the following results: 3. Mean cell residence time- 5 day, MLSS concentration in the reactor 7.200 mg/L...
Environmental Engineering 3&4
So 3. An activated sludge plant treats 5 MGD and the average influent BOD is 200 mg/L. The WWTP has 2 aeration basins, each 100 ft x 25 ft x 15 ft deep and 2 final clarifiers with diameters of 20 ft. About 35% of BOD is removed in primary clarifiers. Determine the BOD in the primary effluent, hydraulic retention time, F/M ratio, BOD exiting the aeration basin and mass of solids wasted (1b/d). The operation parameters...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of raw wastewater to be treated is 20 MGD in the design year, the dissolved BODs is 380 mg/L, and SS is 360 mg/L. The wastewater generated by the sludge treatment process is about 4 MGD with the dissolved BODs being 1800 mg/L, and SS being 1200 mg/L, and will be returned to the wet well in the pumping station at the beginning of the...
A complete-mix activated sludge system is used to treat municipal wastewater after primary sedimentation at 20 °C with MLVSS concentration of 2000 g/m3. The discharge standard for soluble BOD, concentration in the effluent is 0.5 g/m. The characteristics of the primary influent are: flow Q -2000 m'/d, soluble BOD -200 g/m3, Using these data and the kinetic coefficients in following, determine 1. Theoretical solids retention time (SRT) in unit of days 2. Pk vss in unit of kg VSS/d 3....
just part e please
Activated sludge design A completely mixed activated sludge process is designed to treat 20,000 m/day of domestic wastewater having a BODs concentration of 250 mg/L following primary treatment. The NPDES permit requires that the effluent BOD, and TSS concentra- tions not exceed 20 mg/L on an annual basis. The following biokinetic coefficients are to be used in the design of the process: Y = 0.6 mg VSS/mg BODs, k = 5d"! Ks = 60 mg/L BODs,...
CIEG 328 HOMEWORK7 Homework 7 (Suspended growth) Due: 4/112019 Design an activated sludge biological treatment system for a typical medium-strength domestic wastewater with a design daily flow of 2.9 million gallons per day. Assume the plant effluent criteria are 10/10/1" This means that the plant must produce an effuent with average BODS and TSS concentrations of 10 mg/Leach year round, and an effluent ammonia concentration of 1 mg/L as N during the winter months. The layout of the plant will...
A regional STP handles wastewater from 22,000 people where the per capita flow is assumed to be 380 L/person/day. This STP comprises (in series) a primary settler, a trickling filter, two facultative ponds, and a mature constructed wetland. The table below gives typical values (all in mg/L) for the overflow stream after the primary settler (APS) and for the final treated effluent (FTE). Parameter APS FTE Suspended solids 120 2 Biochemical oxygen demand 130 3 Total nitrogen (as N) 30...