What is the equilibrium constant of the formation reaction of ammonia gas at 298.15 K under the conditions that the partial pressures of N2, H2 and NH3 are 2.00 bar, 3.00 bar, and 2.00 bar, respectively? (Hint: Be careful! This is a trick question! The equilibrium constant is what it is. It is not dependent on what the partial pressures happen to be at any particular time. K is purely dependent on the standard Gibbs free energy of the reaction..)
What is the equilibrium constant of the formation reaction of ammonia gas at 298.15 K under...
1. The simplest ammonia formation is from nitrogen and hydrogen. Consider the reversible reaction N2(g) + 3H2(g) → 2NH3(g) The standard enthaply and Gibbs free energy of formation one mole NH3 is ∆H◦ m = −46.11 kJ mol−1 and ∆G◦ m = −16.78 kJ mol−1 . (a) What is equilibrium constant at standard condition (25°C and 1 atm)? (b) What is equilibrium constant at 60°C and 1 atm? (c) What is the Gibbs free-energy change relative to that under standard...
What would you calculate as the equilibrium ratio once the equilibrium position is reached for ammonia synthesis reaction? Starting with the initial concentrations of Nh3= 2.00 M, N2 = 2.00 M, and H2 = 2.00. N2+3 H2 - > 2 NH3 (Hint: may be a trick question)
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 bar for all species. For the reaction N2(g)+3H2(g)↽−−⇀2NH3(g) the standard change in Gibbs free energy is Δ?∘=−69.0 kJ/mol. What is Δ? for this reaction at 298 K when the partial pressures are ?N2=0.500 bar, ?H2=0.150 bar, and ?NH3=0.750 bar? Show work please!
The reaction for the formation of ammonia is shown as: N2(g) + 3 H2(g) ⇄ 2 NH3(g) Kc=? Write the equilibrium constant expression (Kc) for this reaction. Calculate the value of Kc at 500. K for the formation of ammonia in part a) using the following measured concentrations for the equilibrium mixture: [N2] = 3.0 x 10-‐2 M; [H2] = 3.7 x 10-‐2 M; [NH3] = 1.6 x 10-‐2 M. [1.7 x 102] Now, calculate the value of Kc for the formation of...
For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 bar for all species. For the reaction N2(g) + 3 H2(g) = 2 NH3(g) the standard change in Gibbs free energy is AGⓇ = -72.6 kJ/mol. What is AG for this reaction at 298 K when the partial pressures are PN, = 0.200 bar, Ph, = 0.150 bar, and PnHz = 0.800 bar. kJ AG = mol
a.) Calculate the equilibrium constant for the following reaction at 298.15 K from cell potential data. Express the answer as lnK. Sn4+ + 2Fe2+ ----> Sn2+ + 2Fe3+ b.) Calculate the standard Gibbs free energy change in kJ/mol at 298.15 K for the following reaction from cell potential data: 3Sn4+ + 2Cr ----> 3Sn2+ + 2Cr3+
At 400 K, the reaction N2 (g) + 3 H2 (g) → 2 NH3 (g) reaches equilibrium when the partial pressures of nitrogen, hydrogen, and ammonia gases are 4.00 atm, 1.00 atm, and 1.05 x 10−2 atm, respectively. Given that the standard enthalpy of the reaction at 400K is DH = -94 kJ/mol, estimate the value of the equilibrium constant KP at 450 K assuming that the standard enthalpy of reaction does not vary significantly with temperature in this temperature...
The equilibrium constant, K, for the Haber reaction is 2.81 x 10^-5 at 472 C, if a reaction STARTS with 3 bar of H2, and 5 bar of N2 at 472 C, what is the equilibrium pressure of NH3? be sure to justify whether or not any assumptions made the calculations appropriate. N2 (g) + 3 H2 (g) == 3NH3 (g)
12) The equilibrium constant, Kp, is 4.51x10 at 450°C for the reaction represented below. N2(g) + 3 H2(g) 2 NH3(g) a. Write the equilibrium expression, Kp, for the reaction. b.Suppose y ou start out with only reactants in a rigid container. The initial partial pressure of N2(g) is 1.0 atm and that of H2(g) is 1.4 atm. What are the partial pressures of each species when the system reaches equilibrium? c. Find K, for this process at 450°C.
Write the equilibrium constant expression for the reaction of nitrogen and hydrogen to give ammonia, NH3. Express your answer in terms of concentrations [N2], [H2], and [NH3].