Consider the reaction. 2 A ( g ) − ⇀ ↽ − B ( g ) K p = 9.80 × 10 − 5 at 500 K If a sample of A ( g ) at 4.90 atm is heated to 500 K , what is the pressure of B ( g ) at equilibrium?
2A(g) -----> B(g) , Kp = 9.80*10^-5
4.90 0 (at t=0)
4.90-2x x (at equilibrium)
Kp = P(B) / (P(A))^2
9.80*10^-5 = x / (4.90-2x)^2
0.000098 * (4.90-2x)^2 = x
0.000392x^2 - 1.0019208x + 0.00235298 = 0
Solving quadratic equation;
We get x = 0.00235
So, at equilibrium;
Pressure of B = 0.00235 atm ...Answer
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