Find the area under the standard normal curve that lies between z = 1.62 and z = 3.22.
solution
z = 1.62 and z = 3.22.
P( 1.62< Z <3.22 )
= P(Z <3.22 ) - P(Z <1.62 )
Using z table,
=0.9994-0.9474
area=0.0520
Find the area under the standard normal curve that lies between z = 1.62 and z...
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